Since force is a vector quantity, we can find the net force by determining the resultant force. The equation is written below:
F = √(Fx²)+(Fy)²
where
Fx is the force parallel to the ground
Fy is the downward force
F = √(1.2×10⁻⁶ N)²+(1.27×10⁻⁵ N)²
F = 1.2788×10⁻⁵ N
Then, we apply Newton's second law of motion.
F = ma
a = F/m = 1.2788×10⁻⁵ N/(6×10⁻⁷ kg)
a = 21.31 m/s²
<em>The magnitude of the acceleration is 21.31 m/s². The direction is shown in the picture, which is headed towards southeast.</em>
F = √(Fx²)+(Fy)²
where
Fx is the force parallel to the ground
Fy is the downward force
F = √(1.2×10⁻⁶ N)²+(1.27×10⁻⁵ N)²
F = 1.2788×10⁻⁵ N
Then, we apply Newton's second law of motion.
F = ma
a = F/m = 1.2788×10⁻⁵ N/(6×10⁻⁷ kg)
a = 21.31 m/s²
<em>The magnitude of the acceleration is 21.31 m/s². The direction is shown in the picture, which is headed towards southeast.</em>