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yawa3891 [41]
3 years ago
11

A girl exerts a horizontal force of 109 N on a crate with a mass of 31.2 kg. HINT (a) If the crate doesn't move, what's the magn

itude of the static friction force (in N)? 109 Correct: Your answer is correct. The static friction force is fs ≤ μsn. For an object with no acceleration at rest on a surface, fs equals the particular value required to keep the object at rest on the surface. N (b) What is the minimum possible value of the coefficient of static friction between the crate and the floor? (Assume the crate remains stationary.)
Physics
1 answer:
vesna_86 [32]3 years ago
7 0

Answer:

(a) Magnitude of static friction force is 109 N

(b) Minimum possible value of static friction is 0.356

Solution:

As per the question;

Horizontal force exerted  by the girl, F = 109 N

Mass of the crate, m = 31.2 kg

Now,

(a) To calculate the magnitude of static friction force:

Since, the crate is at rest, the forces on the crate are balanced and thus the horizontal force is equal to the frictional force, f:

F = f = 109 N

(b) The maximum possible force of friction between the floor and the crate is given by:

f_{m} = \mu_{s}N

where

N = Normal reaction = mg

Thus

f_{m} = \mu_{s}mg

For the crate to remain at rest, The force exerted on the crate must be less than or equal to the maximum force of friction.

f\leq f_{m}

f \leq \mu_{s}mg

109 \leq \mu_{s}\times 31.2\times 9.8

\mu_{s}\geq 0.356

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Answer:

0.67m/s²

Explanation:

Given parameters:

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Unknown:

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Solution:

According to newton's second law of motion;

      Force  = mass x acceleration

Now,

      Acceleration = \frac{Force}{mass}

     Acceleration  = \frac{0.8}{1.2}   = 0.67m/s²

4 0
3 years ago
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Simon is riding a bike at 12 km/h away from his friend Keesha.He throws a ball at 5 km/h back to Keesha, who is standing still o
Tems11 [23]

I notice that even though we're working with frames of reference
here, you never said which frame the '5 km/hr' is measured in.

In fact !  You didn't even say which frame the '12 km/hr' of his
bike is measured in.

So there are several different ways this could go.  I'll do it the way
I THINK you meant it, but that doesn't guarantee anything.

-- Simon is riding his bike at 12 km/hr relative to the sidewalk,
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-- He throws a ball at Keesha, at 5 km/hr relative to his own face.

-- Keesha sees the ball approaching her at (12 - 5) = 7 km/hr
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5 0
3 years ago
To pull an old stump out of the ground, you and a friend tie two ropes to the stump. You pull on it with a force of 500 N to the
zhannawk [14.2K]

Answer:

C. less than 950 N.

Explanation:

Given that

Force in north direction F₁ = 500 N

Force in the northwest F₂ = 450 N

Lets take resultant force R

The angle between force = θ

θ = 45°

The resultant force R

R=\sqrt{F_1^2+F_2^2+2F_1F_2cos\theta}

R=\sqrt{500^2+450^2+2\times 450\times 500\times cos\theta}

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C. less than 950 N

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8 0
3 years ago
Which statement best summarizes the central idea of “Applications of Newton’s Laws”?
Shkiper50 [21]

 

Newton's three forces, normal, tension and friction, are present in a surprising number of physical situations

Newton's Laws, that describe the relationship between an obejct and the forces acting upon it, apply in almost every physical situation, from quantum mechanics to electricity.

The correct answer is:

Newton’s laws can explain the forces that occur between objects every day


3 0
3 years ago
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What is the altitude of the Sun at noon on December 22, as seen from a place on the Tropic of Cancer?
scZoUnD [109]

Answer:

108.217 °

Explanation:

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90+Latitude-Declination angle

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∴ Altitude angle of the Sun as seen from the tropic of cancer on December 22 is 108.217 °

4 0
3 years ago
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