1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yawa3891 [41]
3 years ago
11

A girl exerts a horizontal force of 109 N on a crate with a mass of 31.2 kg. HINT (a) If the crate doesn't move, what's the magn

itude of the static friction force (in N)? 109 Correct: Your answer is correct. The static friction force is fs ≤ μsn. For an object with no acceleration at rest on a surface, fs equals the particular value required to keep the object at rest on the surface. N (b) What is the minimum possible value of the coefficient of static friction between the crate and the floor? (Assume the crate remains stationary.)
Physics
1 answer:
vesna_86 [32]3 years ago
7 0

Answer:

(a) Magnitude of static friction force is 109 N

(b) Minimum possible value of static friction is 0.356

Solution:

As per the question;

Horizontal force exerted  by the girl, F = 109 N

Mass of the crate, m = 31.2 kg

Now,

(a) To calculate the magnitude of static friction force:

Since, the crate is at rest, the forces on the crate are balanced and thus the horizontal force is equal to the frictional force, f:

F = f = 109 N

(b) The maximum possible force of friction between the floor and the crate is given by:

f_{m} = \mu_{s}N

where

N = Normal reaction = mg

Thus

f_{m} = \mu_{s}mg

For the crate to remain at rest, The force exerted on the crate must be less than or equal to the maximum force of friction.

f\leq f_{m}

f \leq \mu_{s}mg

109 \leq \mu_{s}\times 31.2\times 9.8

\mu_{s}\geq 0.356

You might be interested in
An apple is whirled round in a horizontal circle on the end of a string which is tied to the stalk. It is whirled faster and fas
jek_recluse [69]

when the apple moves in a horizontal circle, the tension force in the string provides the necessary centripetal force to move in circle. the tension in the string is given as

T=mv²/r

where T = tension force in the string , m = mass of the apple

v = speed of apple , r = radius of circle.

clearly , tension force depends on the square of the speed. hence greater the speed, greater will be the tension force.

at some point , the speed becomes large enough that it makes the tension force in the string becomes greater than the tensile strength of the string. at that point , the string breaks

6 0
3 years ago
WILL MARK BRAINLIEST
rodikova [14]

Answer:

152,155 J

Explanation:

115,333 + 36,822 = 152,155J

8 0
2 years ago
A bumper cart has a mass of 200 kg and has a protective bumper around it that behaves like a spring. The spring constant is 5000
34kurt
Part A:
For this part we’re assuming all the kinetic energy of the moving bumper car is converted into elastic potential energy in the spring since the car is brought to rest. Therefore you can find the total kinetic energy to get your answer:

KE = ½ mv^2
KE = ½ (200)(8)^2
KE = 6400 J

Part B:
Now you can use Hooke’s law to find the force:

F = kx
F = (5000)(0.2)
F = 1000 N
4 0
3 years ago
When an electron moves 2.5 m in the direction of an electric field, the change in electrical potential energy of the electron is
anygoal [31]
In the field of electromagnetism, when two charged plates that are situated opposite to each other by a certain distance, it forms an energy called the electric field. This energy is due to the difference in potential energy with respect to distance. Thus,

E = V/d

However, the voltage in volts is energy per coulomb. Thus,
V = (8x10-17 J/electron)*(1electron/1.60218x10^-19 C)
V = 499.32 volts

Therefore,

E = 499.32 volts /2.5 m
E = 199.73 N/C

The electric field that caused the change in potential energy is equal to 199.73 Newtons per Coulomb.
7 0
3 years ago
Assume that the polymer material has a constant refractive index of 1.5. For light of 600nm wavelength at normal incidence, what
yaroslaw [1]

Answer:

Minimum thickness will be 100 nm

Explanation:

We have given refractive index is n = 1.5

Wavelength of the light incidence \lambda= 600 nm

We have to find the smallest thickness of the film so that there will be minimum light reflect

For minimum thickness of non reflecting film

t=\frac{\lambda }{4n} , here t is thickness, \lambda is wavelength and n is refractive index

Putting all values t=\frac{600}{4\times 1.5}=100nm

So minimum thickness will be 100 nm

8 0
3 years ago
Other questions:
  • Discuss the phase change condition due to reflection of light from a surface. Summarize equations of interference for thin film.
    11·1 answer
  • Which part of an atom is responsible<br>fon the flow of electricity?*​
    11·1 answer
  • Two carts, one of mass 2m and one of mass m, approach each other with the same speed, v. When the carts collide, they
    10·1 answer
  • You serve a tennis ball from a height of 1.80 m above the ground. The ball leaves your racket with a velocity of 18.0 m/s at an
    11·1 answer
  • Describe Charle’s Law and Boyle’s Law.
    5·1 answer
  • Convert the value of g=9.8m/s^2 into km/hr^2​
    13·1 answer
  • HELPP!!!! URGENT!!!!
    11·1 answer
  • A sonar signal leaves a submarine, travels through
    11·1 answer
  • Write down the principals of them lever in points .​
    12·1 answer
  • The temperature of an air parcel and the kinetic energy of an air parcel are ___________ related. this means that as the tempera
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!