Answer:
Diameter of wire B is 2 times the diameter of wire A
Explanation:
We have given two wire A and B
They are made up of same material and length of both the wire is sane
So 
Let the resistivity of both the wire is 
It is given that wire A has 4 times the resistance as wire B
So 
So 
( As )
So diameter of wire B is 2 times the diameter of wire A
The compound is (Sulphuric Acid) H2SO4. On reacting with (Sodium Hydroxide) NaOH, it gives (2 Water Molecules/Colored) 2H2O and (1 Sodium Sulfate Molecule/Salt) Na2SO4
H2SO4 + NaOH —> 2H2O (aq.) + Na2SO4 (salt)
The resulted salt/compound (Na2SO4) when reacting with Methyl Orange (MO) is called ”Removal of methyl orange dye and Na2SO4 salt from synthetic wastewater using reverse osmosis (RO)”
The efficiency of reverse osmosis (RO) membranes used for treatment of colored water effluents can be affected by the presence of both salt and dyes.
Concentration polarization of each of the dye and the salt and the possibility of a dynamic membrane formed by the concentrated dye can affect the performance of the RO membrane.
The objective of the current work was to study the effect of varying the Na2SO4 salt and methyl orange (MO) dye concentrations on the performance of a spiral wound polyamide membrane.
The work also involved the development of a theoretical model based on the solution diffusion (SD) mass transport theory that takes into consideration a pressure dependent dynamic membrane resistance as well as both salt and dye concentration polarizations.
Control tests were performed using distilled water, dye/water and salt/water feeds to determine the parameters for the model.
The experimental results showed that increasing the dye concentration from 500 to 1000 ppm resulted in a decrease in the salt rejection at all of the operating pressures and for both feed salt concentrations of 5000 and 10,000 ppm.
Increasing the salt concentration from 5000 to 10,000 ppm resulted in a slight decrease in the percent dye removal. The model’s results agreed well with these general trends.
For both NPN and PNP this is true:
The base is between the collector and the emitter.
<em> In a refracting telescope </em><u><em>convex lens</em></u><em> forms the image.
</em>
<u>Answer:</u> <em>c. Convex mirror</em>
<u>Explanation:</u>
Telescope is an instrument used for magnification of distant objects. The convex lenses objective and eyepiece are the two parts of a refracting telescope.
Objective has a greater focal length when compared with the eyepiece. Image of a distant object is formed at the second focal point of the objective. This image is magnified by the eyepiece.
The objective and eyepiece lenses can only produce an inverted image since they both are convex lenses. The function of producing a final erect image is performed by a pair of inverting lenses.
Answer:
HERE IS YOUR ANSWER
Explanation:
PLEASE MARK MY ANSWER AS BRAINLIEST IF THE ANSWERS ARE CORRECT .
Beacuse of the loose connection of the wire .
Straight
