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Fittoniya [83]
1 year ago
15

he electric motor of a model train accelerates the train from rest to 0.720 m/s in 29.0 ms. The total mass of the train is 840 g

. Find the average power delivered to the train during its acceleration. W
Physics
1 answer:
kkurt [141]1 year ago
4 0

Answer:

7.481W

Explanation:

power= work done÷time

power= force × uniform velocity

a= ∆v/t

29.0ms=

29 \times  {10}^{ - 3 } s

=(0.72-0)÷29×10^-3

a=24.83m/s^2

Newton's second law

f=ma

=(0.84×24.83)

=20.86N

w=FD

v^2=u^2+2as

0.5184=0+49.66s

s=0.0104m

20.86×0.0104

=0.216944J

0.216944÷t

P=7.481W

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please help me guys please please please please please please please please please please please please please​
Maurinko [17]
Someone write the answers???

5 0
2 years ago
Read 2 more answers
A spider begins to spin a web by first hanging from a ceiling by his fine, silk fiber. He has a mass of 0.025 kg and a charge of
Rasek [7]

Answer:

a) (5.59 × 10³) N/C

b) 0.226 N directed away from the spider.

Explanation:

a) Electric field, E, felt as a result of point charge, Q, at a distance, d away is given by

E = kQ/d²

So, magnitude of the electric field due to the charge on the second spider at the position of the first spider

Q = 4.2 µC = 4.2 × 10⁻⁶ C

k = Coulomb's constant = 8.99 × 10⁹ Nm²/C

d = 2.6 m

E = (8.99 × 10⁹ × 4.2 × 10⁻⁶)/2.6²

E = 5.59 × 10³ N/C

b) Tension in the silk fiber above the spider is the net force due to the weight of spider one and the force of repulsion due the two charges.

Force due to the two charges = Eq

where q now represents the charge of the first spider at the first point, feeling the electric field calculated in (a)

F = 5.59 × 10³ × 3.4 × 10⁻⁶ = 0.01901 N directed upwards. (That is, F = + 0.019 N)

Weight of the spider = mg = 0.025 × 9.8 = 0.245 N directed downwards. (That is, W = -0.245 N)

Net force, T = mg - F = 0.245 - 0.019 = 0.226 N (that is, 0.226 N, directed upwards, away from the spider).

8 0
3 years ago
Reese can run 10 meter in 5 seconds.What is her speed?
Bad White [126]

Answer:

2 meters per second

Explanation:

4 0
3 years ago
A 0.23 kg ladle sliding on a horizontal frictionless surface is attached to one end of a horizontal spring (k = 580 N/m) whose o
Anna71 [15]

Answer:

Explanation:

Angular speed of the motion ( SHM )

ω = √k/m

= √(580/.23 )

= 50.20 radian /s

a ) Rate of doing work

= power = force x velocity

At the equilibrium position force becomes zero so

rate of doing work is zero.

b )

If a be the amplitude

1/2 k a² = 170

a = .7655 m

kinetic energy at equilibrium = 1/ 2 m v₀²

1/ 2 m v₀² = 170

.5 x  23  v₀² = 170

v₀ = 3.84 m /s which is the maximum velocity.

Given x = .66 where rate of doing work is to be calculated.

Force at x = ω² x

= 50.20² x .66 =

= 1663.22 N

Velocity v = v₀ √( a² - x² )

= 3.84 √( .7655² - .66 )

= 3.84 x .387

= 1.486 m/s

power = force x velocity

=  1663.22 x 1.486

= 2471.55  W .

3 0
2 years ago
Use what you know about mass and how you use it to calculate force in the following situation. If each washer has a mass of 4. 9
mina [271]

Considering the change of units and the definition of weight, the mass of two washers would be 0.0098 kg and if 4 washers are attached to the string, then the applied force on the car will be 0.196 N.

  • <u><em>Mass of two washers</em></u>

If each washer has a mass of 4.9 g, then the mass of two washers will be calculated simply by multiplying the mass of 1 washer by the amount you have of them, in this case 2:

4.9 g×2= 9.8 g

Being 1 kg = 1000 g, you apply the following rule of three to make the change of units: if 1000 g equals 1 kg, 9.8 g equals how many kilograms?

mass=\frac{9.8 gramsx1 kg}{1000g}

Solving:

<u><em>mass= 0.0098 kg</em></u>

Finally, the mass of two washers would be 0.0098 kg.

  • <u><em>Applied force</em></u>

On the other side, mass is the amount of matter that a body contains and weight is the action exerted by the force of gravity on the body.

The mass of an object will always be the same, no matter where it is located. Instead, the weight of the object will vary according to the force of gravity acting on it.

Weight is calculated as the product of the object's mass and the value of the gravitational acceleration:

W= m×g

In this case, you know:  

  • m= 4.9 g×4= 19.6 g= 0.0196 kg → the mass of 4 washers in kilograms
  • g= 10 m/s²

Replacing:

W= 0.0196 kg× 10 m/s²

Solving:

<u><em>W= 0.196 N</em></u>

Finally, if 4 washers are attached to the string, then the applied force on the car will be 0.196 N.

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7 0
2 years ago
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