Question

he electric motor of a model train accelerates the train from rest to 0.720 m/s in 29.0 ms. The total mass of the train is 840 g. Find the average power delivered to the train during its acceleration. W

Answer 1

Answer:

7.481W

Explanation:

power= work done÷time

power= force × uniform velocity

a= ∆v/t

29.0ms=

$29 \times {10}^{ - 3 } s$

=(0.72-0)÷29×10^-3

a=24.83m/s^2

Newton's second law

f=ma

=(0.84×24.83)

=20.86N

w=FD

v^2=u^2+2as

0.5184=0+49.66s

s=0.0104m

20.86×0.0104

=0.216944J

0.216944÷t

P=7.481W