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3 years ago

A mixture can be classified as a solution, suspension, or colloid based on the

Physics

1 answer:

atroni [7]3 years ago

8 0

The best answer choice here is B. =)

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Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant

ExtremeBDS [4]

Answer:

Final Speed: 26m/s

Explanation:

7 0

3 years ago

A 7 kg ball of clay traveling at 12 m/s collides with a 25 kg ball of clay traveling in the

ANEK [815]

Answer:

Given: 

m1 = 7 kg

V1 = 12 m/s

m2 = 25 kg

V2 = 6 m/s

To find:

Combined speed of two balls stick together after collision V = ?

Solution:

According to law of conservation of momentum,

m1V1 + m2V2 = (m1+m2)V

7×12 + 25×6 = (7+25)V

84 + 150 = 32V

V = 234/32

V = 7.31 m/s

Combined speed of two ball is 7.31 m/s

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4 0

2 years ago

A failure of the red-sensitive nerves in the eye to respond to light properly causes

allochka39001 [22]

Color blindness is the failure of the red sensitive nerves in the eye that don't respond to light properly.

3 0

3 years ago

Read 2 more answers

Nitric acid (HNO3) and potassium hydroxide (KOH) combine in a neutralization reaction to form water and a salt. Which of the fol

mrs_skeptik [129]

Answer:

The answer to your question is KNO₃

Explanation:

Data

HNO₃

KOH

neutralization reaction

Process

1.- In a neutralization reaction an acid reacts with an alkali and the products are water and a binary or ternary salt.

Reactants acid = HNO₃ alkali = KOH

A neutralization reaction is a double displacement reaction so the salt formed is.

HNO₃ + KOH ⇒ H₂O + KNO₃

Potassium nitrate

5 0

3 years ago

Read 2 more answers

What minimum heat is needed to bring 250 g of water at 20 ∘C to the boiling point and completely boil it away? The specific heat

Amiraneli [1.4K]

Answer:633.8 KJ

Explanation:

Given

mass of water $\left ( m\right )=250gm$

Initial temperature $\left ( T_i\right )=20^{\circ}C$

Final temperature $\left ( T_f\right )=100^{\circ}C$

Specific heat of water $\left ( c \right )$ =4190 J/kg-k

heat of vaporization $\left ( L\right )=22.6\times 10^5 J/kg$

Heat required for process $\left ( Q\right )$ =heat to raise water temperature from 20 to 100 +Heat to vapourize water completely

Q=mc $\left ( T_f-T_i\right )+mL$

Q= $0.25\times 4190\times \left ( 100-20\right )+0.25\times 22\times 10^5$

Q= $\left ( 0.838+5.5\right )\times 10^5$

Q= $6.338\times 10^5J=633.8 KJ$

4 0

4 years ago