The particle is an electron. The field slows down the electron without deflecting it. The direction of the electric field is <u>right.</u>
In physics, the motion of electrically charged particles gives rise to a field called an electric field. It is measured in force per unit charge.
This field applies force on other charged particles.
Particles bearing opposite charges attract each other while particles having similar charges repel each other in the field.
If a positive charge is placed in the field then the field line moves in an outward direction and for a negative charge, the direction of the lines is inward.
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For this question we should apply
a = v^2 - u^2 by t
a = 69 - 0 by 4.5
a = 69 by 4.5
a = 15.33
a = 6.85 m/s^2
If the answer in option is near to answer then , you can mark it as correct.
.:. The acceleration is 6.9 m/s^2
Explanation:
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<span>The velocity would be 54.2 m/s
We would use the equation 1/2mv^2top+mghtop = 1/2mv^2bottom+mghbottom where m is the mass of the bobsled(which can be ignored), vtop/bottom is the velocity of the bobsled at the top or bottom, g is gravity, and htop/bottom is the height of the bobsled at the top or bottom of the hill. Since the velocity of the bobsled at the top of the hill and height at the bottom of the hill are zero, 1/2mv^2top and mghbottom will equal zero. The equation will be mghtop=1/2mv^2bottom. Thus we would solve for v.</span>
