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MArishka [77]
3 years ago
8

What is the name of the instrument used to measure amount of substance? ​

Physics
2 answers:
DENIUS [597]3 years ago
5 0

Answer:

The word stoichiometry is a technical chemical term derived from the two Greek roots stoicheion, "element", and metron, "measure". Chemical stoichiometry is the area of chemistry which deals with the quantitative relationships between numbers of atoms involved in matter. Since very large numbers of atoms are needed to make up real objects which we can conveniently handle, the unit of amount of substance contains a large number of atoms. That unit of amount of substance is called the mole.

Explanation:

just olya [345]3 years ago
3 0

Answer:

The mole is the SI (stoichiometry) unit for ammount of substance

Explanation:

hope this helps

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Draw graph for positive acceleration, negative acceleration and zeo acceleration​
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Explanation:

horizontal is zero slope, and the vertical is undefined

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Estimate the order of magnitude of the length, in
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<span>b) Easy = 1 meter </span>

<span>c) two choices 10m or 100 m . Go with 100 m </span>

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3 years ago
You are measuring the mass of different chemicals to get ready to conduct an experiment.
vova2212 [387]

Answer:

B) grams

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3 0
3 years ago
Read 2 more answers
A 113 kg man sits on the stern of a 6.3 m long boat. The prow of the
Usimov [2.4K]

Answer:

m = 105.37 kg

Explanation:

We are given;

Mass of man; m = 113 kg

Length of boat = 6.3m

Now, The position of the center of mass will not change during the motion of the man.

Thus,

X_g,i = X_g,f

So,

[113(6.3) + ma]/(113 + m) = [113(3.26) + m(a +3.26)]/(113 + m)

113 + m will cancel on both sides to give;

113(6.3) + ma = [113(3.26) + m(a +3.26)]

711.9 + ma = 368.38 + ma + 3.26m

ma will cancel out to give;

711.9 - 368.38 = 3.26m

343.52/3.26 = m

m = 105.37 kg

3 0
3 years ago
The force an ideal spring exerts on an object is given by Fx = -kx, where x measures the displacement of the object from its equ
shusha [124]

Answer:

The work done by this force can be found via the following formula

W = \int{F(x)} \, dx = \int\limits^0_{-20} {(-kx)} \, dx = \frac{-kx^2}{2}\left \{ {{x=0} \atop {x=-20}} \right. = \frac{-60*(-20)^2}{2} \\W = -12000J

Explanation:

Alternatively, the work done by the object is equal to the elastic potantial energy done by the spring.

U = \frac{1}{2}kx_2^2 - \frac{1}{2}kx_1^2 =0 - \frac{1}{2}60(-20)^2 = -12000J

6 0
3 years ago
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