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Lyrx [107]
3 years ago
13

Round 5,704 to the nearest hundred

Mathematics
2 answers:
Elza [17]3 years ago
6 0

Answer:

0

Step-by-step explanation:

0

Rounded to the nearest 100 or

the Hundreds Place.

andreyandreev [35.5K]3 years ago
3 0

Answer:

5,700

Step-by-step explanation:

5,704 rounds down to 7,500 because it is not 7,550 if it was that or above then your answer would be correct 100% but its not

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In this arithmetic sequence, what is the common difference? -19, -11, -3, 5
OLga [1]

Answer:

8

Step-by-step explanation:

find the pattern -19+8=-11, -11+8=-3, -3+8=5

8 0
2 years ago
Solve 8x = 1 quick plz
Ulleksa [173]

Answer:

x = 1/8 = 0.125

Step-by-step explanation: Add 1 to both sides of the equation :

8x = 1

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4 0
3 years ago
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Dmitrij [34]

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Read 2 more answers
Lim x-1 x2 - 1/ sin(x-2)
balu736 [363]

Answer:

           \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0

Explanation:

Assuming the correct expression is to find the following limit:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}

Use the property the limit of the quotient is the quotient of the limits:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}

Evaluate the numerator:

          \frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}

Evaluate the denominator:

  • Since         \lim_{x \to1}sin(x-2)\neq 0

                  \frac{0}{\lim_{x \to1}sin(x-2)}=0

4 0
2 years ago
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andreev551 [17]
It’s 54 because I did the math to get the answer
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2 years ago
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