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3 years ago

Expand and simplify:(x + 1)(2x - 3)with the explaining the steps

Mathematics

2 answers:

Luden [163]3 years ago

8 0

<h3>Answer: 2x^2 - x - 3</h3>

====================================

Work Shown:

(x+1)(2x-3)

y(2x-3)

2xy - 3y

2x( y ) - 3( y )

2x( x+1 ) - 3( x+1 )

2x^2+2x - 3x-3

2x^2 - x - 3

Explanation:

In the second step, I replaced all of (x+1) with y. Afterward, I distributed that y term through. A few steps later, I replaced y with x+1 to help finish up the distributions. You could use the FOIL rule as an alternative approach.

kodGreya [7K]3 years ago

4 0

= X(2X-3) + 1 ( 2X-3)
=(2X*2 -3X) + (2X-3)
=2x*2 - 3X + 2x-3
=2x*2-x-3

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podryga [215]

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2 years ago

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3 years ago

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3 years ago

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3 years ago

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A quadratic function is given. f(x) = 1 + x − 7 x2 (a) Use a graphing device to find the maximum or minimum value of the quadrat

Virty [35]

Answer:

a) $P (x,y) \approx (0.1,1.05)$ , b) $P(x,y) = (0.07,1.04)$ .

Step-by-step explanation:

a) The graphic is enclosed to the problem. By visual inspection, an absolute maximum is found.

$P (x,y) \approx (0.1,1.05)$

b) The exact method consists in the application of the First and Second Derivative Tests. First and second derivatives are, respectively:

$f'(x) = 1 - 14\cdot x$

$f''(x) = -14$

The First Derivative Test consists in equalizing the first derivative to zero and solving the expression:

$1 - 14\cdot x = 0$

$x = 0.07$

According to the second derivative, the critical point leads to a maximum. The remaining component is determined by evaluation the polynomial:

$y = 1 +0.07-7\cdot (0.07)^{2}$

$y = 1.04$

The exact solution is $P(x,y) = (0.07,1.04)$ , indicating that graphic solution leads to a good approximation.

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3 years ago

Expand and simplify:(x + 1)(2x - 3)with the explaining the steps​

Expand and simplify:(x + 1)(2x - 3)with the explaining the steps