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Brilliant_brown [7]
3 years ago
9

Simplify the expression to a polynomial in standard form: (4x-3)(-2x^2-7x-5)

Mathematics
1 answer:
Brums [2.3K]3 years ago
6 0

How to solve your problem

(4−3)(−22−7−5)

(4x−3)(−2x2−7x−5)(4x-3)(-2x^{2}-7x-5)(4x−3)(−2x2−7x−5)

Simplify

1

Distribute

(4−3)(−22−7−5)

(4x−3)(−2x2−7x−5){\color{#c92786}{(4x-3)(-2x^{2}-7x-5)}}(4x−3)(−2x2−7x−5)

4(−22−7−5)−3(−22−7−5)

2

distribute

4(−22−7−5)−3(−22−7−5)

4x(−2x2−7x−5)−3(−2x2−7x−5){\color{#c92786}{4x(-2x^{2}-7x-5)}}-3(-2x^{2}-7x-5)4x(−2x2−7x−5)−3(−2x2−7x−5)

−83−282−20−3(−22−7−5)

3

−83−282−20−3(−22−7−5)

−8x3−28x2−20x−3(−2x2−7x−5)-8x^{3}-28x^{2}-20x{\color{#c92786}{-3(-2x^{2}-7x-5)}}−8x3−28x2−20x−3(−2x2−7x−5)

−83−282−20+62+21+15

4

Solution

−83−222++15

I know this looks like a lot but its just how you solve your problem.

therefor, your answer is

Solution

−83−222++15

<em>Hope this helps!</em>

<em>Have a great day!</em>

<em>-Hailey</em>

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Answer:

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Step-by-step explanation:

According to the order of operations, multiplies all have equal priority. Therefore, they must be evaluated left to right, not right to left. Evaluating (5 x 2) first is incorrect, and instead (9 x 5) should be calculated first.

3 0
2 years ago
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For bone density scores that are normally distributed with a mean of 0 and a standard deviation of​ 1, find the percentage of sc
gogolik [260]

Answer:

a) The percentage of bone density scores that are significantly high is 2.28%

b) The percentage of bone density scores that are significantly low is 2.28%

c) The percentage of bone density scores that are not significant is 95.44%

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

a. significantly high​ (or at least 2 standard deviations above the​ mean).

This is 1 subtracted by the pvalue of Z = 2.

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% of scores are signifcantly high

b. significantly low​ (or at least 2 standard deviations below the​ mean).

pvalue of Z = -2

Z = -2 has a pvalue of 0.0228

2.28% of scores are signicantly low.

c. not significant​ (or less than 2 standard deviations away from the​ mean).

pvalue of Z = 2 subtracted by the pvalue of Z = -2.

Z = 2 has a pvalue of 0.9772

Z = -2 has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

95.44% of the scores are not significant

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3 years ago
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... ∠1 = ∠2

... 3x -5 = 2x +15 . . . . substitute the given values

... x = 20 . . . . . . . . . . . add 5-2x

The measures of angles 1, 2, and 3 are 2·20+15 = 55 . . . degrees.

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Step-by-step explanation:

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Answer:

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