Answer:
The estimated impact of the experiment of offering test preparation classes is:
= 8 scores (in performance improvement).
Step-by-step explanation:
Average standardized-test score for the first 10 high schools = 69
Average standardized-test score for the second 10 high schools = 70
After 6 months:
Average standardized-test score for the first 10 high schools offered test preparation classes = 78
The change in the average standardized-test score for the first 10 high schools = 9 (78 - 69)
Average standardized-test score for the second 10 high schools not offered test preparation classes = 71
The change in the average standardized-test score for the second 10 high schools not offered the prep = 1 (71 - 70)
The estimated impact of the experiment of offering test preparation classes is:
= 9 - 1
= 8.
8.75 x 37.5= ? Well all you do is have to line up the decimals and work it out! :) it's simple
<span>f(x) = 9x-8
y = 9x-8
x = 9y-8
+8 +8
-----------
x+8 = 9y
----- ----
9 9
</span>x+8
----- <span> = y</span>
9
x+8
----- = f^-1 (x) ← Answer
9
Answer:
c=4
Step-by-step explanation:
subtract 50-18= 32
then subtract 12c-4c= 8c
8c=32
divide 8c by 32 which gives you
c=4
