Answer:
(3, 50) and (14,303)
Step-by-step explanation:
Given the system of equations;
y=23x–19 ....1
x²–y= – 6x–23 ...2
Substitute 1 into 2;
x²–(23x-19)= – 6x–23
x²–23x+19= – 6x–23 .
x²-23x + 6x + 19 + 23 = 0
x² - 17x + 42 = 0
Factorize;
x² - 14x - 3x + 42 = 0
x(x-14)-3(x-14) = 0
(x-3)(x-14) = 0
x = 3 and 14
If x = 3
y = 23(3) - 19
y = 69-19
y = 50
If x = 14
y = 23(14) - 19
y = 322-19
y = 303
Hence the coordinate solutions are (3, 50) and (14,303)
Answer:
1.5 in
Step-by-step explanation:
Let x be the width of the frame.
Side of print=10 in
Area of frame=69 square in
We have to find the width of the frame.
Side of frame=10+x+x=10+2x
Area of square=
By using the formula
Area of print=
Area of frame with print=
Area of frame=Area of frame with print-Area of print
Because Side is always positive.
Hence, width of frame=1.5 in
Answer:
1. a
2. b
3. c
4. d
Step-by-step explanation:
Answer:
Step-by-step explanation:
(x^2 - 4)(x^2 - 4)
Simplifying
(x2 + -4)(x2 + -4)
Reorder the terms:
(-4 + x2)(x2 + -4)
Reorder the terms:
(-4 + x2)(-4 + x2)
Multiply (-4 + x2) * (-4 + x2)
(-4(-4 + x2) + x2(-4 + x2))
((-4 * -4 + x2 * -4) + x2(-4 + x2))
((16 + -4x2) + x2(-4 + x2))
(16 + -4x2 + (-4 * x2 + x2 * x2))
(16 + -4x2 + (-4x2 + x4))
Combine like terms: -4x2 + -4x2 = -8x2
(16 + -8x2 + x4)
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