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3 years ago

7

Reduce to the simplest form

alt="\frac{286}{858}" align="absmiddle" class="latex-formula">

1 answer:

Allisa [31]3 years ago

5 0

Answer:

143 over 428

Step-by-step explanation:

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I need help with the questions in the pictures

Inessa [10]

Oh geez they poor lol

6 0

3 years ago

Daniel [21]

Area of the three equally sized stripes: A

A=(x+15)(x)(3)
A=3x(x+15)
A=3x^2+45x

One gallon of paint will cover an area of no more than 400 square feet: <=400

She only has half of a gallon of paint left:
1/2(400 square feet)=400/2=200 square feet

Inequality that could be used to find the maximum height, in feet, of each stripe:
A<=200
3x^2+45x<=200

Answer: 3x^2+45x <= 200

Could her stripes be 3' tall?
x=3→A=3(3)^2+45(3)=3(9)+135=27+135→A=162<200 Ok
Yes, her stripes could be 3' tall.
Answer: Yes

Could her stripes be 4' tall?
x=4→A=3(4)^2+45(4)=3(16)+180=48+180→A=228>200 No
No, her stripes couldn't be 4' tall.
Answer: No

3 0

3 years ago

Drag the numbers to the boxes to order them from least to greatest value.

attashe74 [19]

Hello!

First you have to convert them all into numbers

2 = 2
47/14 = 3.35
sqrt of 5 = 2.23
0.9 = 0.9
0 = 0

Now you list them from least to greatest

The answer is $0, 0.9, 2, \sqrt{5} , \frac{47}{14}$

Hope this helps!

3 0

4 years ago

Can anyone please help me solve this??

Inessa05 [86]

Answer:

X=4 Y= -5

Step-by-step explanation:

7 0

3 years ago

Last question was inncorrectly typed:1.A sample of students who has taken a calculus test has a mean =78.2, mode =67, median 67.

vampirchik [111]

Answer:

(A) The data set of the sample of students who has taken a calculus test is right skewed.

(B) The average of female students in the class is 66.

Step-by-step explanation:

(A)

For a left skewed distribution the Mean < Median < Mode.

For a right skewed distribution the Mean > Median > Mode.

For a symmetric distribution the Mean = Median = Mode.

Given: Mean = 78.2, Median = 67 and Mode = 67

In this case the mean of the data is more than the median and mode.

$Mean = 78.2>Median = Mode = 67$

Thus, the data set of the sample of students who has taken a calculus test is right skewed.

(B)

Total number of student ( $n$ ) = 35

Combined average ( $\mu_{c}$ ) = 70

Number of male student ( $n_{M}$ ) = 20

Average of male students ( $\mu_{M}$ ) = 73

Number of female student ( $n_{F}$ ) = 15

Average of female students = $\mu_{F}$

The formula to compute the combined average is:

$\mu_{c}=\frac{n_{M}\mu_{M}+n_{F}\mu_{F}}{n_{M}+n_{F}}$

Compute the value of $\mu_{F}$ as follows:

$\mu_{c}=\frac{n_{M}\mu_{M}+n_{F}\mu_{F}}{n_{M}+n_{F}}\\70=\frac{(20\times73)+(15\times\mu_{F})}{20+15}\\ 70\times35=1460+(15\times\mu_{F})\\\mu_{F}=\frac{2450-1460}{15} \\=66$

Thus, the average of female students in the class is 66.

8 0

4 years ago