The value of Vz at point z from the generator = 17.748 ∠ -107.62° V
<u>Given data :</u>
Internal resistance = 50 ohms
Vg = 10 ∠ 0° v
length of air line = 3.6 m
Terminating resistance = 25 + j25 Ω
<u />
<u>First step : Determine the </u><u>Total impedance </u>
Total Impedance ( z ) = Rin + Rline + Rl + jXl
= 50 + 50 + 25 + j25
= 125 + j25 ≈ 127.47 ∠ 11.3°
<u></u>
<u>Next step : Determine the </u><u>curren</u><u>t in the circuit </u>
current ( I ) = Vg / z
= ( 10∠0° v ) / ( 127.47 ∠ 11.3° )
= 0.0784 ∠ -11.3 amp
<u />
<u>Final step</u><u> : Determine the value of Vz at point z from the generator </u>
Vz = ( Vg + I * Ri ) - ( RI * I + Rline * I )
= ( 10∠0° + 0.0784 ∠ -11.3 * 50 ) - ( 25 + j25 + 50 * 0.0784 ∠ -11.3 )
= -5.37 - j16.91 ≈ 17.748 ∠ -107.62° V
Hence we can conclude that the value of Vz at point z form the generator 17.748 ∠ -107.62° V
Learn more about voltage : brainly.com/question/11288970
Hello your question is incomplete below is the complete question
<u><em>A 100 MHz generator with Vg =10< 0 degree (v) and internal resistance 50-ohm is connected to a lossless 50-ohm air line that is 3.6m long and terminated in a 25+j25 (ohm) load.
</em></u>
<u><em>
Find (a) V(z) at a location z from the generate.</em></u>
