Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
The answer is equal to -0.6
AP and BQ are medians of the triangle ABC and K is the centroid of the triangle.
One of the properties of the medians is that the point of intersection divides the median in the ratio 2:1
So BK = 2 KQ therefore
15 = 2 * KQ
and KQ = 7.5 answer
Well the first thing you have to do is find out how many times 7 goes into 50 whole. This is 7. So then you take the answer to (7x7) from 50 which gives you one, and put it over 50. This equals 7 + 1/50
