1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
White raven [17]
3 years ago
14

There are currently 2,732 students enrolled at a local community college. The student population is projected to increase at a r

ate of 4% each year. Which choice represents the total student population as a function of time?
Mathematics
2 answers:
Juliette [100K]3 years ago
5 0
What are the options? I think it is y=.04x +2732
alexandr402 [8]3 years ago
5 0
The answer is B. f(x)=2,732* 1.04
You might be interested in
Consider a group of 1,000 newborn infants. One hundred (100) infants were born with serious birth defects, and 20 of these 100 d
kozerog [31]

Answer:

The prevalence of serious defects in this population at the time of birth is 10%.

Step-by-step explanation:

The prevalence of serious defects is the number of infants that were born with seriours birth defects divided by the total number of infants born.

In this problem, we have that:

There were 1000 newborn infants.

100 infants were born with serious birth defects.

Calculate the prevalence of serious defects in this population at the time of birth.

This is:

P = \frac{10}{100} = 0.1

The prevalence of serious defects in this population at the time of birth is 10%.

8 0
3 years ago
A full glass of water can hold of a bottle.
zloy xaker [14]

Answer:

three bottles of water can hold three glass of water

Step-by-step explanation:

one glass of water = one bottle

3 0
4 years ago
Suppose two dice are tossed and the numbers on the upper faces are observed. Let S denote the set of all possible pairs that can
Thepotemich [5.8K]

Answer:

▪A = {(1,2) (1,4) (1,6) (2,2) (2,4) (2,6) (3,2) (3,4) (3,6) (4,2) (4,4) (4,6) (5,2) (5,4) (5,6) (6,2) (6,4)(6,6)}

▪C bar = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)}

▪A∩B = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)}

▪A∩B bar = {(1,2) (1,4) (1,6) (3,2) (3,4) (3,6) (5,2) (5,4) (5,6)}

▪A bar∪B = {(1,1) (1,3) (1,5) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,3) (3,5) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,3) (5,5) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)}

▪A bar∩C = {(1,1) (1,3) (1,5) (2,1) (2,3) (2,5) (3,1) (3,3) (3,5) (4,1) (4,3) (4,5) (5,1) (5,3) (5,5) (6,1) (6,3) (6,5)}

Step-by-step explanation:

S = {(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)}

A = {(1,2) (1,4) (1,6) (2,2) (2,4) (2,6) (3,2) (3,4) (3,6) (4,2) (4,4) (4,6) (5,2) (5,4) (5,6) (6,2) (6,4)(6,6)} (second die is even)

B = {(1,1) (1,3) (1,5) (2,2) (2,4) (2,6) (3,1) (3,3) (3,5) (4,2) (4,4) (4,6) (5,1) (5,3) (5,5) (6,2) (6,4) (6,6)} (sum of the two numbers is even)

C = {(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,3) (2,5) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,3) (4,5) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,3) (6,5)} (at least one in the pair is odd i.e one of the pair is odd or both are odd)

A bar = {(1,1) (1,3) (1,5) (2,1) (2,3) (2,5) (3,1) (3,3) (3,5) (4,1) (4,3) (4,5) (5,1) (5,3) (5,5) (6,1) (6,3) (6,5)} (the pairs that are not in A)

B bar = {(1,2) (1,4) (1,6) (2,1) (2,3) (2,5) (3,2) (3,4) (3,6) (4,1) (4,3) (4,5) (5,2) (5,4) (5,6) (6,1) (6,3) (6,5)} (the pairs that are not in B)

C bar = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)} (the pairs that are not in C)

▪A = {(1,2) (1,4) (1,6) (2,2) (2,4) (2,6) (3,2) (3,4) (3,6) (4,2) (4,4) (4,6) (5,2) (5,4) (5,6) (6,2) (6,4)(6,6)}

▪C bar = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)}

▪A∩B = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)} (intersection: the pairs that are common to both A and B)

▪A∩B bar = {(1,2) (1,4) (1,6) (3,2) (3,4) (3,6) (5,2) (5,4) (5,6)} (intersection: the pairs that are common to both A and B bar)

▪A bar∪B = {(1,1) (1,3) (1,5) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,3) (3,5) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,3) (5,5) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)} (union: all the pairs in A bar and B )

▪A bar∩C = {(1,1) (1,3) (1,5) (2,1) (2,3) (2,5) (3,1) (3,3) (3,5) (4,1) (4,3) (4,5) (5,1) (5,3) (5,5) (6,1) (6,3) (6,5)} (intersection: the pairs that are common to both A bar and C)

6 0
3 years ago
A fair coin is tossed 6 times. Compute the probability of tossing 6 tails in a row.
Fofino [41]

Answer:

1/6

Step-by-step explanation:

5 0
4 years ago
How is everybody doing in there life?
denis23 [38]

Answer:

I'm doing okay i miss school and my friends

5 0
3 years ago
Other questions:
  • Find the length of the diameter of a sphere with a surface area of 50.27 ft^2.
    9·1 answer
  • What's the measurements of angle U and angle Q. If angle X is 147.2 degrees and angle Y is 32.8 degrees. Explain your reasoning.
    7·1 answer
  • Also this question tooo pleease, PS: what topic is this <br> Solve for x.
    7·1 answer
  • Let ​ f(x)=x2+5x−8​.
    14·2 answers
  • If m□ebd=4x-8 and m□ebc=5x+20,find the value of x and m□ebc
    7·1 answer
  • How to divied and multiply fraction but in word problems
    13·1 answer
  • Can someone help me please
    10·1 answer
  • A store buys a camera for $80 and decides to markup the price 35%. How much does the camera sell for?
    9·1 answer
  • Sara needs to take a taxi to get to the movies. The taxi charges $6 for the first mile, and then $2.75 for each mile after that
    15·2 answers
  • A company that teaches self-improvement seminars is holding one of its seminars in Middletown. The company pays a flat fee of $1
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!