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2 years ago

5

A scale model of a rectangular building lot measures 7feet by 5 feet. If the actual house will be built using a scale factor of

12 what is the area of the actual building lot

1 answer:

Tamiku [17]2 years ago

5 0

Actual area of the rectangular building = 5040 feet²
Step-by-step explanation:
Length of the rectangular building = 7 feet
Width of the rectangular building = 5 feet
Now, The building is made with a scale factor of 12
So, Actual length of the rectangular building = 84 feet
Actual width of the rectangular building = 60 feet
Now, Actual area of the rectangular building = Length × Width
⇒ Actual area of the rectangular building = 84 × 60
⇒ Actual area of the rectangular building = 5040 feet²

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The ratio of the measures of the three angle in a triangle is 15:8:13. Find the measure of the three angles.

Angelina_Jolie [31]

Answer:

a=15x; b=8x; c=13x

180°=a+b+c=15x+8x+13x=36x

=> x=180÷36=5

=> a=15×5=75°; b=8×5=40°; c=13×5=65°

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2 years ago

The graph of f(x) and g(x) are shown below

Jlenok [28]

Answer:

c

Step-by-step explanation:

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2 years ago

Is 9.521521521 rational or irrational

enyata [817]

If the numbers after the decimal terminate, yes, it's rational.

9.521521521 = 9,521,521,521 / 1,000,000,000

If they don't terminate, but the pattern continues (which I suspect is the case here), yes, it's still rational.

If <em>x</em> = 9.521521521…, then

1000<em>x</em> = 9521.521521521…

Subtract <em>x</em> from this to eliminate the fractional part:

1000<em>x</em> - <em>x</em> = 9521.521521521… - 9.521521521…

999<em>x</em> = 9512

<em>x</em> = 9512/999

If they don't terminate, but the pattern does <em>not</em> continue, meaning the next few digits could be something random like

9.521521521<u>19484929271283583457</u>…

then the number would be irrational.

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2 years ago

Can anyone help me integrate :

worty [1.4K]

Rewrite the second factor in the numerator as

$2x^2+6x+1=2(x+2)^2-2(x+2)-3$

Then in the entire integrand, set $x+2=\sqrt3\sec t$ , so that $\mathrm dx=\sqrt3\sec t\tan t\,\mathrm dt$ . The integral is then equivalent to

$\displaystyle\int\frac{(\sqrt3\sec t-2)(6\sec^2t-2\sqrt3\sec t-3)}{\sqrt{(\sqrt3\sec t)^2-3}}(\sqrt3\sec t)\,\mathrm dt$
$=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\sqrt{\sec^2t-1}}\,\mathrm dt$
$=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\sqrt{\tan^2t}}\,\mathrm dt$
$=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{|\tan t|}\,\mathrm dt$

Note that by letting $x+2=\sqrt3\sec t$ , we are enforcing an invertible substitution which would make it so that $t=\mathrm{arcsec}\dfrac{x+2}{\sqrt3}$ requires $0\le t$ or $\dfrac\pi2$ . However, $\tan t$ is positive over this first interval and negative over the second, so we can't ignore the absolute value.

So let's just assume the integral is being taken over a domain on which $\tan t>0$ so that $|\tan t|=\tan t$ . This allows us to write

$=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\tan t}\,\mathrm dt$
$=\displaystyle\int(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\csc t\,\mathrm dt$

We can show pretty easily that

$\displaystyle\int\csc t\,\mathrm dt=-\ln|\csc t+\cot t|+C$
$\displaystyle\int\sec t\csc t\,\mathrm dt=-\ln|\csc2t+\cot2t|+C$
$\displaystyle\int\sec^2t\csc t\,\mathrm dt=\sec t-\ln|\csc t+\cot t|+C$
$\displaystyle\int\sec^3t\csc t\,\mathrm dt=\frac12\sec^2t+\ln|\tan t|+C$

which means the integral above becomes

$=3\sqrt3\sec^2t+6\sqrt3\ln|\tan t|-18\sec t+18\ln|\csc t+\cot t|-\sqrt3\ln|\csc2t+\cot2t|-6\ln|\csc t+\cot t|+C$
$=3\sqrt3\sec^2t-18\sec t+6\sqrt3\ln|\tan t|+12\ln|\csc t+\cot t|-\sqrt3\ln|\csc2t+\cot2t|+C$

Back-substituting to get this in terms of $x$ is a bit of a nightmare, but you'll find that, since $t=\mathrm{arcsec}\dfrac{x+2}{\sqrt3}$ , we get

$\sec t=\dfrac{x+2}{\sqrt3}$
$\sec^2t=\dfrac{(x+2)^2}3$
$\tan t=\sqrt{\dfrac{x^2+4x+1}3}$
$\cot t=\sqrt{\dfrac3{x^2+4x+1}}$
$\csc t=\dfrac{x+2}{\sqrt{x^2+4x+1}}$
$\csc2t=\dfrac{(x+2)^2}{2\sqrt3\sqrt{x^2+4x+1}}$

etc.

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2 years ago

Explain the difference between simple interest and compound interest.

USPshnik [31]

Simple interest:

Simple interest is simple. Each year, the interest is calculated as a percentage of the principal, as follows: Interest= (principal) x (rate) x (time).

Compound interest:

Compound interest<span> is calculated on the principal amount and also on the accumulated </span>interest <span>of previous periods.</span>

8 0

2 years ago