Question

If an electron has an acceleration of 2.33 × 102 m/sec2, what is this value in units of m/min2?

Answer 1

Answer:

The electron has an acceleration of 838800 $\frac{m}{min^{2} }$

Explanation:

An electron has an acceleration of 2.33*10² $\frac{m}{sec^{2} }$

To be able to express in units $\frac{m}{min^{2} }$, you must carry out the conversion taking into account that 1 $\frac{m}{sec^{2} }$= 3600 $\frac{m}{min^{2} }$. Then you can apply the following rule of three: if 1 $\frac{m}{sec^{2} }$ equals 3600 $\frac{m}{min^{2} }$, 2.33 * 10² $\frac{m}{sec^{2} }$ equals how much $\frac{m}{min^{2} }$?

$\frac{m}{min^{2} }=\frac{2.33*10^{2} \frac{m}{sec^{2} }*3600\frac{m}{min^{2} }}{1\frac{m}{sec^{2} }}$

$\frac{m}{min^{2} }=838800$

The electron has an acceleration of 838800 $\frac{m}{min^{2} }$