Answer:
If the temperature of gas is decreased the pressure will also goes to decrease.
Explanation:
The pressure and temperature have direct relation. If the temperature of gas will increase the pressure of gas will also goes to increase.
According to the Gay-Lussas's Law,
The pressure of given amount of gas is directly proportional to the absolute temperature when volume is kept constant.
Mathematical relationship:
P ∝ T
P = kT
P/T = k
and
P₁/T₁ = P₂/T₂
Answer:
Explanation:
A reactant is a substance that is present at the start of a chemical reaction. The substance(s) to the right of the arrow are called products . A product is a substance that is present at the end of a chemical reaction.
h2 + 02 = h2o
<h2 />
<span>Answer is </span>(3)
- Sodium Nitrate.<span>
</span>Normally ionic bonds can be seen between
metals and non-metals while covalent
bonds present between
non-metals. Another thing that determines the bond nature is electronegativity
value of the atoms.
If the electronegativity difference
is high, then that bond tends to be an ionic bond.<span>
</span><span>Sodium nitrate consists of </span>Na⁺<span> and </span>NO₃⁻ ions. Hence, the bond
between Na⁺ and NO₃⁻<span> is an </span>ionic
bond. <span><span>
NO</span>₃⁻ </span><span>is made from </span>N <span>and </span>O<span>. Both are </span>non-metallic
atoms. <span>The </span>electronegativities <span>of </span>N <span>and </span>O <span>are </span>3.0 <span>and </span>3.5 <span>respectively. Hence, there is </span>no
big difference between
electronegativity values (3.5 - 3.0 = 0.5<span>). Hence, the bond
between N and O is a </span><span>covalent
bond. </span>
Respuesta:
2 FeCl₃(aq) + 3 Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + 6 NaCl(aq)
Explicación:
Consideremos la ecuación no balanceada que ocurre cuando cloruro férrico acuoso reacciona con carbonato de sodio sólido para formar carbonato férrico sólido y cloruro de sodio acuoso. Esta es una reacción de doble desplazamiento.
FeCl₃(aq) + Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + NaCl(aq)
Vamos a usar el método de tanteo. Empezaremos balanceando los átomos de C, multiplicando Na₂CO₃ por 3.
FeCl₃(aq) + 3 Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + NaCl(aq)
Luego, balancearemos los átomos de Fe, multiplicando FeCl₃ por 2.
2 FeCl₃(aq) + 3 Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + NaCl(aq)
Finalmente, obtendremos la ecuación balanceada, multiplicando NaCl por 6.
2 FeCl₃(aq) + 3 Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + 6 NaCl(aq)
