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vlada-n [284]
3 years ago
11

Water is capable of dissolving a variety of different substances, which is why it is such a good solvent. It is often called the

universal solvent because it dissolves more substances than any other liquid. The reason for this is best explain by which of these? A) Water is polar with a positive and negative side. B) Water is the most abundant liquid on earth. C) Water bonds with most chemicals. D) Water expands as it freezes.
Chemistry
1 answer:
Serggg [28]3 years ago
6 0

Answer:

Explanation:

In this case the answer would be

Water is a polar molecule with positive and negative side

Now since these negative and positives are present in the water molecule . In easy terms when a substance reacts with water .the negative part of water ( oxygen ) reacts with the positive part of the substance and the positive part of the water ( hydrogen) reacts with negative part of the substance .if you look at the reason . Water is held up by one of the strongest attraction forces available .since most substances have weaker attraction forces between them ,therefore water can easily overcome them with its forces. Thus giving it the ability to dissolve a variety of substances

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Answer:

2 only

Explanation:

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3 years ago
The vapor pressure of benzene at 298 K is 94.4 mm of Hg. The standard molar Gibbs free energy of formation of liquid benzene at
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Answer:

ΔfG°(C₆H₆(g)) = 129.7kJ/mol

Explanation:

Bringing out the parameters mentioned in the question;

Vapor pressure = 94.4 mm of Hg

The vaporization reaction is given as;

C₆H₆(l) ⇄ C₆H₆(g)

Equilibrium in terms of activities is given by:

K = a(C₆H₆(g)) / a(C₆H₆(l))

Activity of pure substances is one:

a(C₆H₆(l)) = 1

Assuming ideal gas phase activity equals partial pressure divided by total pressure. At standard conditions

K = p(C₆H₆(g)) / p°

Where p° = 1atm = 760mmHg standard pressure

We now have;

K = 94mmHg / 760mmHg = 0.12421

Gibbs free energy is given as;

ΔG = - R·T·ln(K)

where R = gas constant = 8.314472J/molK

So ΔG° of vaporization of benzene is:

ΔvG° = - 8.314472 · 298.15 · ln(0.12421)

ΔvG° = 5171J/mol = 5.2kJ/mol  

Gibbs free energy change of reaction = Gibbs free energy of formation of products - Gibbs free energy of formation of reactants:

ΔvG° = ΔfG°(C₆H₆(g)) - ΔfG°(C₆H₆(l))

Hence:

ΔfG°(C₆H₆(g)) = ΔvG°+ ΔfG°(C₆H₆(l))

ΔfG°(C₆H₆(g)) = 5.2kJ/mol + 124.5kJ/mol

ΔfG°(C₆H₆(g)) = 129.7kJ/mol

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Answer:

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