Prime numbers are numbers that can be divided without a remainder. So 2181 is divisible by 3 and 727 and there is no remainder.
The perimeter of ΔXYZ is 126 units.
Solution:
Given ΔPQR
ΔXYZ.
In ΔPQR,
PQ = 5, QR = 10, PR = 6
In ΔXYZ, XY = 30
Perimeter of ΔPQR = PQ + QR + PR
= 5 + 10 + 6
= 21
Perimeter of ΔPQR = 21
To find the perimeter of ΔZYZ:
If two triangles are similar then the ratio of the perimeters of two similar triangles is same as the ratio of their corresponding sides.


Do cross multiplication, we get
⇒ 5 × Perimeter of ΔXYZ = 30 × 21
⇒ 5 × Perimeter of ΔXYZ = 630
Divide by 5 on both sides of the equation.
⇒ Perimeter of ΔXYZ = 126
Hence the perimeter of ΔXYZ is 126 units.
Answer:The roots are: √11 + 2 and -√11 + 2
Explanation:First, we would put the equation in the standard form which is as follows:
ax² + bx + c = 0
This can be done as follows:
x² - 4x + 4 - 11 = 0
x² - 4x - 7 = 0
By comparison:
a = 1
b = -4
c = -7
Now, to get the roots, we would use the quadratic equation shown in the attached image.
By substitution, we would find that:
either x = √11 + 2
or x = -√11 + 2
Hope this helps :)