Answer:
k = 652 lb/ft
Explanation:
Given :
Weight of the collar = 1.6 lb
The upstretched length of the spring = 6 in
Speed = 16 ft/s
PA = 8 + 10
= 18 inch
Let the initial elongation be 
∴ = 18 - 6
= 12 inch = 1 foot
= 13.925 inch
Final elongation in the spring
inch = 0.66 feet
Applying the conservation of the mechanical energy between A and B is
![$\frac{1}{2}k[(1)^2-(0.66)^2]=\frac{1.6}{2}\times (16)^2-1.6 \times 32 \times \frac{5}{12}$](https://tex.z-dn.net/?f=%24%5Cfrac%7B1%7D%7B2%7Dk%5B%281%29%5E2-%280.66%29%5E2%5D%3D%5Cfrac%7B1.6%7D%7B2%7D%5Ctimes%20%2816%29%5E2-1.6%20%5Ctimes%2032%20%5Ctimes%20%5Cfrac%7B5%7D%7B12%7D%24)
k = 652 lb/ft
Answer:
Explanation:
Assuming there is no waste of energy:
Answer:
(a) Total north component = (26.89 + 25) = 51.89 metres
(b) Total west component = (-34.83 + 52) = 17.17 metres.
Explanation:
Do northwest components first.
North component = (sin 33.9 x 44) =26.89 metres.
West component = (cos 33.9 x 44) = -34.83metres.
Total west component = (-34.83 + 52) = 17.17 metres.
Total north component = (26.89 + 25) = 51.89 metres
Answer:
Precision
Explanation:
You can be very precise but inaccurate, as described . You can also be accurate but imprecise. For example, if on average, your measurements for a given substance are close to the known value, but the measurements are far from each other, then you have accuracy without precision. Precision is independent of accuracy. You can be very precise but inaccurate, as described above. You can also be accurate but imprecise. For example, if on average, your measurements for a given substance are close to the known value, but the measurements are far from each other, then you have accuracy without precision. Precision refers to the closeness of two or more measurements to each other. Using the example above, if you weigh a given substance five times, and get 3.2 kg each time, then your measurement is very precise.
