Answer:
a) 40 V
b) 69.23 V
c) 69.23 V
Explanation:
See attachment for solution
Answer: 31.6ft
Explanation:
Check the attachment for the diagram.
According to the right angle triangle AEC, we will use Pythagoras theorem to get |AC|. Note that |AE| = |AB| - |CD|
that is 20ft - 10ft = 10ft
According to the theorem, the square of the sum of the adjacent side and the opposite side is equal to the square of the hypotenuse.
|AE|^2 + |EC|^2 = |AC|^2
10^2 + 30^2 = |AC|^2
100 + 900 = |AC|^2
|AC| = √1000
|AC| = 31.6ft
Therefore, the wire should be anchored 31.6ft to the ground to minimize the amount of wire needed.
Answer:
Explanation:
Total resistance of 2 bulb in series
= 100 +100 = 200 ohm
current in each bulb
= 9/200 = .045 A
In case of parallel combination of bulb
total resistance
= 100 x 100 / (100+100)
50 ohm
current in the main circuit
= 9 / 50 A
current in each bulb
= 9 / (2 x 50)
.09
So in the second case current is more , hence heat generated too will be more . So brightness too will be more.
First set ( in series ) will be dimmer.
Not sure if this is what you’re looking for. Let me know if I can clarify anything.
In a parallel circuit, the total resistance calculated from the individual resistances is computed from the formula: 1/Rt = 1/R1 + 1/R2. substituting R1 and R2, then
1/Rt = 1/7 + 1/49
1/Rt = 1/6.125 = 1/ 49/8
Rt = 49/8 <span>Ω
The total resistance hence is </span>49/8 Ω