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SpyIntel [72]
3 years ago
15

Explain why liquid particles at a high pressure would need more energy to change to a gas than liquid particles at a low pressur

e.
Physics
1 answer:
jenyasd209 [6]3 years ago
8 0
Jsjsjjewiqoowodofofocpcco Ossis
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Which theory of language development and acquisition includes the concepts of reinforcement, stimuli control, deprivation, and a
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A pendulum can be formed by tying a small object, like a tennis ball, to a string, and then connecting the other end of the stri
Usimov [2.4K]

Answer:

1- t^3

2- t^2

3- t1

Explanation:

The acceleration produced in a body, while travelling in a circular motion, due to change in direction of motion is called centripetal acceleration. The formula of the centripetal acceleration is as follows:

ac = v²/r

where,

ac = centripetal acceleration

v = speed

r = radius

for a constant radius the centripetal acceleration will be directly proportional to the speed of object. The speed of pendulum will be lowest at t1 due to zero speed initially. Then the speed will increase gradually having greater speed at t^2 and the highest speed and centripetal acceleration at t^3. Therefore, the three instants in tie can be written in following order from greatest centripetal acceleration to lowest:

<u>1- t^3</u>

<u>2- t^2</u>

<u>3- t1</u>

5 0
3 years ago
A car accelerates uniformly from rest to 24.8 m/s in 7.88 s along a level stretch of road. Ignoring friction, determine the aver
nevsk [136]

Answer:

When he weight of the car is 8.55 x 10^{3} N then power = 314.012 KW

When he weight of the car is 1.10 x 10^{4}  N then power =  43.76 KW

Explanation:

Given that

Initial velocity V_{1} = 0

Final velocity V_{2} = 24.8 \frac{m}{s}

Time = 7.88 sec

We know that power required to accelerate the car is given by

P = \frac{change \ in \ kinetic \ energy}{time}

Change in kinetic energy Δ K.E = \frac{1}{2} m (V_{2}^{2} - V_{1}^{2}   )

Since Initial velocity V_{1} = 0

⇒ Δ K.E = \frac{1}{2} m V_{2}  ^{2}

⇒ Power P = \frac{1}{2} \frac{m}{t}  V_{2} ^{2}

⇒ Power P = \frac{1}{2} \frac{W}{g\ t}  V_{2} ^{2}   -------- (1)

(a). The weight of the car is 8.55 x 10^{3} N = 8550 N

Put all the values in above formula

So power P = \frac{1}{2} \frac{8550}{(9.81)\ (7.88)} (24.8) ^{2}

P = 314.012 KW

(b). The weight of the car is 1.10 x 10^{4} N = 11000 N

Put all the values in equation (1) we get

P = \frac{1}{2} \frac{11000}{(9.81)\ (7.88)} (24.8) ^{2}

P = 43.76 KW

5 0
3 years ago
How far does a car travel in 0.75h if it is moving at a constant speed of 88km/h
Citrus2011 [14]
V=D/T - formula for speed 
88 km/h = D / 0.75 hours - multiply speed and time
66 km= D
D is distance
D= 66 km 
Hope this helps
6 0
3 years ago
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