Median and IQR are the most appropriate measures of center and spread for this data set.
<h3>Why are
Median and IQR the most appropriate?</h3>
Among the 3 central tendencies that includes the mean, median and mode; the median is the better measure because of the followings:
- Mean is affected by extreme values
- Mean is not correct if more outliers are present
- Mean may not represent the nature of the data whether skewed right or left.
Also, the median as the middle entry is not affected by extreme items or outliers, so the median is better than mean,
Furthermore, for the measure of spread, the IQR is better since extreme items will show higher std deviation and also some outliers mislead.
Therefore, Option B is correct.
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To find area we multiple length by width
20 times 45 is 900
then multiply that by 2 because there are two floors that are that size
900 times 2 is 1800
the total area for both floors is 1800 square feet
Let x be your first alloy
2/5x+7/10(30-x)=1/2(30)
4x+210-7x=150
3x=60
x=20
So, you need 20 lbs of the first alloy, and 10 parts of the second to make 30 lbs of half iron and half silver alloy!
1. 3x^1 + 8 - (2x^2 + 1).....distribute the negative thru the parenthesis
3x^1 + 8 - 2x^2 - 1....now combine like terms
-2x^2 + 3x^1 + 7
2. 5x^2 + 3x - 4 - (x^2 - 6x)...same thing..distribute
5x^2 + 3x - 4 - x^2 + 6x...combine like terms
4x^2 + 9x - 4
Answer:
16, 74
Step-by-step explanation:
3x +10 + 12x +50 = 90
15x + 60 = 90
15x = 90 -60
15x = 30
x = 30/15
x = 2
3x + 10 = 3*2 +10 = 6 +10 = 16
12x + 50 = 12*2 +50 = 24 + 50 = 74
