Answer:
100
Step-by-step explanation:
The population is changing linearly. This means that the population is increasing by a particular value n every year.
From 2009 to 2017, there are 8 increases and so, the population increases by 8n.
The population increased from 1700 to 2500. Therefore, the population increase is:
2500 - 1700 = 800
This implies that:
8n = 800
=> n = 800/8 = 100
The average population growth per year is 100.
Answer:
3:11
Step-by-step explanation:
3x=11y
<u>Rearrange to the format of the ratio.</u>
11y = 3x
<u>Let's find </u><u>y/x</u><u>. </u><u>y/x</u><u> is </u><u>y:x.</u>
11y = 3x
<u>Divide both sides by </u><u>11</u><u>.</u>
11y/11 = 3x/11
y = 3x/11
<u>NOW LET'S DIVIDE BOTH SIDES BY </u><u>x</u><u> TO GET </u><u>x</u><u> AS THE DENOMINATOR OF </u><u>y</u><u>.</u>
y = 3x/11
y/x = (3x/11)/x
y/x = (3x/11) * 1/x
y/x = 3/11
Therefore, y:x = 3:11
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Answer:
idk
Step-by-step explanation:
Answer:
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Step-by-step explanation:
answer mujha nahi pata aaaaaaaaaàaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
Answer:
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
Step-by-step explanation:
for
I= ∫x^n . e^ax dx
then using integration by parts we can define u and dv such that
I= ∫(x^n) . (e^ax dx) = ∫u . dv
where
u= x^n → du = n*x^(n-1) dx
dv= e^ax dx→ v = ∫e^ax dx = (e^ax) /a ( for a≠0 .when a=0 , v=∫1 dx= x)
then we know that
I= ∫u . dv = u*v - ∫v . du + C
( since d(u*v) = u*dv + v*du → u*dv = d(u*v) - v*du → ∫u*dv = ∫(d(u*v) - v*du) =
(u*v) - ∫v*du + C )
therefore
I= ∫u . dv = u*v - ∫v . du + C = (x^n)*(e^ax) /a - ∫ (e^ax) /a * n*x^(n-1) dx +C = = (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
