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stiv31 [10]
3 years ago
15

NEED HELP ASAP!!!!!!!

Mathematics
1 answer:
Elan Coil [88]3 years ago
3 0
I think the answer is C
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Y = x2+6x+8 and y = (x+2)(x+4) both define the same quadratic function. Without graphing, identify the x- and y-intercepts of th
mash [69]

Answer:

x-int:(-2,0)(-4,0) . y-int:(0,8)

Step-by-step explanation:

y = x2+6x+8 and y = (x+2)(x+4)

x-int:

x+2=0

x= -2

(-2,0)

x-int:

x+4=0

x=-4

(-4,0)

y-int: plug 0 for x

y=(0+2)(0+4)

y=8

(0,8)

3 0
3 years ago
Determine whether the statement below is always, sometimes, or never true. two lines with positive slopes are parallel.
elena-s [515]
Always because according to my calculations 
8 0
3 years ago
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An HP laser printer is advertised to print text documents at a speed of 18 ppm (pages per minute). The manufacturer tells you th
aliya0001 [1]

Answer:

0.227 = 22.7% probability that the mean printing speed of the sample is greater than 18.12 ppm.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 17.42 ppm and a standard deviation of 3.25 ppm.

This means that \mu = 17.42, \sigma = 3.25

Sample of 12:

This means that n = 12, s = \frac{3.25}{\sqrt{12}}

Find the probability that the mean printing speed of the sample is greater than 18.12 ppm.

This is 1 subtracted by the p-value of Z when X = 18.12.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{18.12 - 17.42}{\frac{3.25}{\sqrt{12}}}

Z = 0.75

Z = 0.75 has a pvalue of 0.773.

1 - 0.773 = 0.227

0.227 = 22.7% probability that the mean printing speed of the sample is greater than 18.12 ppm.

4 0
3 years ago
Out of 300 animals in the zoo 45 are birds what percent are not birds
Leya [2.2K]

Answer:

85%

Step-by-step explanation:

There are two ways to solve this.

1. You can find the percent of birds, and then subtract that from 100%.

To find the percent of birds, divide 45/300 or make the denominator 100 by dividing both parts by 3.

45/300 (as a fraction)

=15/100

That is the same as 15%.

Subtract that from 100% and you get 85%.

2. You find the number of non-bird animals and make that a percent.

300-45=255 non-bird animals

255/300 (as a fraction)

=85/100

That is the same as 85%.

So either way, the answer is 85%.

8 0
3 years ago
Tarin organized this table to determine the number of adults, a, and children attending a fundraiser based on the total number o
slava [35]

Answer:

A, B, and E

Step-by-step explanation:

I finished this question on edge, i swear this is the right answer

7 0
3 years ago
Read 2 more answers
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