#4(a)
row-seat: 3- 13, 4-15, 5-17, 6-19, 7-21
(b)
the equation works for row 1 but not for any of the rows after this
Ex: Row 2, S=7(2)+2, this would equal 14 but there isn't 14 seats in row #2
(c)
S=2(1)+7, there is 9 seats in row 1
2(2)+7=11, there is 11 seats in row 2
2(3)+7= 13, there is 13 seats in row 3
(d)
2(15)+7=37
2*15=30, 30+7=37
(e)
91=2(r)+7
91-7=2(r)+7-7
84=2(r)
84/2=2(r)/2
42=r, the row with 91 seats is row 42
100%/x%=20/15
(100/X)*x=20/15*x --I multiply both sides of the equation by X
100=1.33333333333*x --I divided both sides of the equation by .........................................(1.33333333333) to get X
100/1.33333333333=x
75=x
x=75
15 is 75% of 20
Yes you can. The quadrilateral that you would get is called parallelogram. It has 2 paris of parallel lines. and 2 pairs of equal angles. one pair is angles that are less than 90 degrees and other one is where 2 angles are greater than 90 degrees each. Therefore there isnt any right angle there and you got yourself quadrilateral. of these 2 parallel lines are of equal lenght than you get something called rhombus.
