Answer:
Step 1 : Plug values into the quadratic formula
x = -(-5) +/- √ (-5)^2 - (4)(2)(-3) / (2)(2)
Step 2 : Solve
x = 5 +/- √ 25 + 24 / 4
x = 5 +/- √ 49 / 4
x = 5 +/- 7 / 4
x1 = 5 - 7 / 4 AND x2 = 5 + 7 /4
x1 = -1/2 OR - 0.5
x2 = 3
Hope this helps!!
Answer:
sin(α+β)/sin(α-β) ==(tan α+tan β)/(tan α-tan β )
Step-by-step explanation:
We have to complete
sin(α+β)/sin(α-β) = ?
The identities that will be used:
sin(α+β)=sin α cos β+cos α sin β
and
sin(α-β)=sin α cos β-cos α sin β
Now:
= sin(α+β)/sin(α-β)
=(sin α cos β+cos α sin β)/(sin α cos β-cos α sin β)
In order to bring the equation in compact form we wil divide both numerator and denominator with cos α cos β
= (((sin α cos β+cos α sin β))/(cos α cos β ))/(((sin α cos β-cos α sin β))/(cos α cos β))
=((sin α cosβ)/(cos α cos β )+(cos α sin β)/(cos α cos β ))/((sin α cos β)/(cos α cos β )-(cos α sin β)/(cos α cos β))
=(sin α/cos α + sin β/cos β )/(sin α/cos β - sin β/cos β)
=(tan α+tan β)/(tan α-tan β )
So,
sin(α+β)/sin(α-β) ==(tan α+tan β)/(tan α-tan β)
Answer:
13104
Step-by-step explanation:
9C2 x 14C3 = 36 x 364
= 13104
In the above problem, you want to find the number of multiples of 7 between 30 and 300.
This is an Arithmetic progression where you have n number of terms between 30 and 300 that are multiples of 7. So it is evident that the common difference here is 7.
Arithmetic progression is a sequence of numbers where each new number in the sequence is generated by adding a constant value (in the above case, it is 7) to the preceding number, called the common difference (d)
In the above case, the first number after 30 that is a multiple of 7 is 35
So first number (a) = 35
The last number in the sequence less than 300 that is a multiple of 7 is 294
So, last number (l) = 294
Common difference (d) = 7
The formula to find the number of terms in the sequence (n) is,
n = ((l - a) ÷ d) + 1 = ((294 - 35) ÷ 7) + 1 = (259 ÷ 7) + 1 = 37 + 1 = 38
Answer:
Heya!!
here's your answer
3x^4 − 3x^3 − 3x^2 + 5x −1
