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VLD [36.1K]
3 years ago
6

3 math questions plz help 1.A spherical container has a radius of 1 yard. It is filled with a liquid fuel that costs $10 per cub

ic yard. What is the total value of the fuel in the container? Use 3.14 for π . Enter your answer in the box to the nearest cent.
2.A hollow ball is made of rubber that is 2 cm thick. The ball has a radius to the outside surface of 6 cm. What is the approximate volume of rubber used to make the ball? Use 3.14 to approximate pi. 33.5 cm³ 267.9 cm³ 636.4 cm³ 904.3 cm³

3. A cylinder shaped container has a radius of 30 cm and a height of 100 cm. A glass sphere with a radius of 12 cm is placed inside the cylinder shaped container and then the container is completely filled with water. What is the approximate volume of water contained in the cylinder? Use 3.14 as an approximation for pi. 7,235 cm³ 28,260 cm³ 204,715 cm³ 275,365 cm³
Mathematics
1 answer:
coldgirl [10]3 years ago
4 0
Ill tell u the answer to number 1 in a couple of minutes
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Can someone help me with this question? Whoever helps will get brainliest answer. thank you.
enyata [817]

Answer:

Final answer is x^2.

Step-by-step explanation:

Given expression is x^{\left(\frac{4}{3}\right)}\cdot x^{\left(\frac{2}{3}\right)}

Now we need to find about what is product of both factors.

We see that both factors are in exponent form having equal base "x".

So we can apply formula: x^m\cdot x^n=x^{\left(m+n\right)}

x^{\left(\frac{4}{3}\right)}\cdot x^{\left(\frac{2}{3}\right)}

=x^{\left(\frac{4}{3}+\frac{2}{3}\right)}

=x^{\left(\frac{4+2}{3}\right)}

=x^{\left(\frac{6}{3}\right)}

=x^2

Hence final answer is x^2.

5 0
3 years ago
An object has a mass of 225 g and a volume of 15 cm3.<br> Find the density of the object in g/cm3
ioda

Answer:

D=m/v

=225g/15cm^3

=15g/cm^3

Step-by-step explanation:

The formula for calculating density is: density=mass/volume.

after collecting data you will see that all the data is already in the question and there's no need to convert any units. Divide the mass by the volume and you'll have the density in g/cm^3

5 0
2 years ago
Raymond was asked to solve for the length of the hypotenuse in a right triangle with legs that have side lengths of 4 and 5. His
ohaa [14]

Answer:

Raymond's mistake was on the last step, since he didn't square root both sides

The correct answer should be

c = \sqrt{41}

Step-by-step explanation:

a^2 + b^2 = c^2\\4^2 + 5^2 = c^2\\16 + 25 = c^2\\c^2 = 41\\c = \sqrt{41}

Good luck!

3 0
3 years ago
The area of a rectangular field is 5695 m².
denpristay [2]

Answer:

85 m

Step-by-step explanation:

5696/67=85

3 0
3 years ago
A bank account has a beginning balance of $560.00. After 6 months, the balance in the account has increased to $572.60. What int
Licemer1 [7]
Interest = $572.60 - $560.00 = $12.60

$560 x 6i/12 = $12.60

i = ($12.60 x 12) / ($560 x 6) = 0.045%
7 0
3 years ago
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