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3 years ago

8

PLSSS HELP ASAP DUE TMR MORNING

2 answers:

WINSTONCH [101]3 years ago

8 0

Step-by-step explanation:

Hey there!

Here;

Diameter (d) = 13 ft

Radius (r) = 13/2 = 6.5 ft

Now,

Area of a circle= πr²

= (22/7)*(6.5)²

= 132.78 ft²

Therefore, the area is 133 ft².

<em>Hope</em><em> </em><em>it </em><em>helps!</em>

Svetach [21]3 years ago

6 0

Step-by-step explanation:

Hey there!

Here;

Diameter (d) = 13 ft

Radius (r) = 13/2 = 6.5 ft

Now,

Area of a circle= πr²

= (22/7)*(6.5)²

= 132.78 ft²

Therefore, the area is 133 ft².

Hope it helps!

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Give the slope of y- 4 = 5(x - 2) and a point on the line.

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Answer:

<h2>B. The slope is 5 and (2, 4) is on the line.</h2>

Step-by-step explanation:

The point-slope form of an equation of a line:

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3 years ago

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Answer:

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or

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Step-by-step explanation:

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$v = \pi \int\limit^2_0 ((4x - x^2)^2 - (x^2)^2)\ dx$

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$v = \pi \int\limit^2_0 (16x^2 - 4x^3 - 4x^3 + x^4 - x^4)\ dx$

Simplify like terms

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Integrate

$v = 8\pi [ \frac{2x^{2+1}}{2+1} - \frac{x^{3+1}}{3+1} ]|\limit^2_0$

$v = 8\pi [ \frac{2x^{3}}{3} - \frac{x^{4}}{4} ]|\limit^2_0$

Substitute 2 and 0 for x, respectively

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ \frac{2*0^{3}}{3} - \frac{0^{4}}{4} ])$

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ 0 - 0])$

$v = 8\pi [ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ]$

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$v = 8\pi [ \frac{16*4- 16 * 3}{12}]$

$v = 8\pi [ \frac{64- 48}{12}]$

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Simplify

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The amount that households pay service providers for access to the Internet varies quite a bit, but the mean monthly fee is $50

Natali5045456 [20]

Answer:

(a) See Explanation

(b) $\bar x =50$ and $\sigma_x = 0.8944$

(c) The shape is normal

(d) $P(\bar x > 55) = 0$

Step-by-step explanation:

Given

$\mu = \$50$ -- mean

$\sigma = \$20$ --- standard deviation

$n=500$ --- sample size

Solving (a): The reason we can't determine the probability that an amount to access internet by a household will exceed $55.

The question says that a lot of households pay low rates, but the percentage of the households in this category is not given. This means that it is impossible to determine the shape of the distribution.

Hence, the probability cannot be calculated.

Solving (b): Sample mean and Sample standard deviation

The sample mean estimates the population mean

So:

$\bar x =\mu$

$\bar x =50$

The sample standard deviation is calculated as thus:

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{20}{\sqrt{500}}$

$\sigma_x = \frac{20}{22.36}$

$\sigma_x = 0.8944$

Solving (c): The shape of the distribution.

We have:

$n = 500$ --- The sample size

According to Central limit theorem, When the sample size is greater than 30, then the shape of the distribution is normal.

<em>Hence, the shape is normal</em>

Solving (d): $P(\bar x \ge 55)$

Calculate the test statistic (t)

$t = \frac{\bar x - \mu}{\sigma}$

$t = \frac{55 - 50}{0.8945}$

$t = \frac{5}{0.8945}$

$t = 5.590$

So:

$P(\bar x > 55) = P(t > 5.590)$

Referencing the z table, we have:

$P(t > 5.590) = 0$

Hence:

$P(\bar x > 55) = 0$

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3 years ago