If the work required to stretch a spring 2 ft beyond its natural length is 9 ft-lb,then the work that is needed to stretch it 18 inches beyond its natural length is 81 ft.lb.
Given that work required to stretch a spring 2 ft beyond its natural length is 9 ft-lb.
We are required to find the work that is needed to stretch 18 inches beyond its natural length.
Multiplication is basically finding out the product of two or more numbers.
Work required to stretch the spring 2 feet beyond its natural length=9 ft. lb.
So, to find the work that is required to stretch the spring 18 feet beyond its natural length, we have to multiply 9 with 9 which will give us 81. So the work required is 81 ft.lb.
Hence if the work required to stretch a spring 2 ft beyond its natural length is 9 ft-lb,then the work that is needed to stretch it 18 inches beyond its natural length is 81 ft.-lb.
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Answer:
1/3
Step-by-step explanation:
You need to use slope formula. (the change in Y over the change in X = Slope [x1-x2/y1-y2 = slope]). I believe you can also use point slope formula, but I forgot how to do that one.
First, you would set up the equation.
7-9/-2-4 OR 9-7/4+2
you would then solve to get
-2/-6 OR 2/6
when simplified you get
1/3
for both. Hope it helps!
The answer is no because it fails the vertical line test
Answer:= y = 0.25 to the nearest hundredth.
Step-by-step explanation:
In inverse variation, both variables move in opposite directions. This means that as variable 1 increases, variable 2 reduces and as variable 1 reduces, variable 2 increases.
Y varies inversely with x.
So as y increases, x reduces and as y reduces, x increases.
We would proceed by introducing a constant of variation, k
y = k/x
From the information given,
The constant of variation, k = 1.24
The value if x = 4.96
To find the value of y
y = k/x = 1.24/4.96
= 0.25 to the nearest hundredth.
