The new volume of the balloon : V₂ = 4.89 L
<h3>Further explanation</h3>
Given
V₁ = 4.96 L
T₁ = 6 + 273 = 279 K
T₂ = 2 + 273 = 275 K
Required
The new volume
Solution
Charles's Law
When the gas pressure is kept constant, the gas volume is proportional to the temperature
Input the value :
V₂=V₁.T₂/T₁
V₂ = 4.96 x 275 / 279
V₂ = 4.89 L
Answer:
<h2>Hereis the correct answer </h2>
(A. Au3+ and CI2)
Explanation:
<h3>STUDY CORRECTION. </h3>
Answer:
15.06 L
Explanation:
Using the ideal gas law equation:
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
According to the information provided in this question,
P = 3.50 atm
n = 1.9 moles
V = ?
T = 65°C = 65 + 273 = 338K
Using PV = nRT
V = nRT/P
V = (1.9 × 0.0821 × 338) ÷ (3.5)
V = 52.725 ÷ 3.5
V = 15.06 L
It should follow the law of conservation . A balanced chemical equation occurs when the number of atom in the reactants is equal to the products side
