To balance chemical equations, first determine how many of each are on each side.
MgCl2 + AgNO3 = Mg(NO3)2 + AgCl
1 Mg 1 Mg
2 Cl 1 Cl
1 Ag 1 Ag
1 NO3 2 NO3
Next, we have to get the amounts of elements to equal each other on both sides.
Since there are 2 Cl on the left side and 1 Cl on the right, I'm going to multiply the part on the right that has Cl by 2.
MgCl2 + AgNO3 = Mg(NO3)2 + 2AgCl
1 Mg 1 Mg
2 Cl 2 Cl
1 Ag 2 Ag
1 NO3 2 NO3
We are still unbalanced, since there are more Ag and NO3 on the right than the left. To get them to equal each other, I'm going to multiply the part with the Ag and NO3 on the left by 2.
MgCl2 + 2AgNO3 = Mg(NO3)2 + 2AgCl
1 Mg 1 Mg
2 Cl 2 Cl
2 Ag 2 Ag
2 NO3 2 NO3
Now the equation is balanced!
This is the website I often use to double check to make sure I've balanced correctly: http://www.webqc.org/balance.php
H2SO4 Is The Answer To Your Problem
Answer:
The correct option is A. The salt is more soluble in water since it can form stronger ion-dipole interactions not available to the fatty acid.
Explanation:
An ion-dipole interaction occurs when an ionic compound is placed in a polar solvent. As salts are ionic compounds and water is a polar solvent, so the fatty acid salts will be able to form electrostatic ion-dipole interactions with the polar water molecules. These interactions will cause fatty acid salts to dissolve in water.
The fatty acid is not an ionic compound and will not form the ion-dipole interactions with the water molecules. Hence, fatty acids will be less soluble in water.
Both the batteries and fuel cells are portable resources, which transforms the chemical energy into electrical energy.
A battery will produce electricity from the energy it has accumulated inside the battery, while a fuel cell produces the electricity from the fuel in an external fuel tank. This signifies that while a battery may run dead, a fuel cell will produce electricity as long as there is a supply of fuel.
I think the the state <span>of the air in an isolated room is completely specified by the temperature and the pressure. Since it is isolated, the volume would be the same as the room. Gas is specified by temperature, pressure and volume. Having the values for pressure and temperature then the gas is completely specified. Hope this answers the question.</span>