1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vaieri [72.5K]
3 years ago
6

Compare the solubility of a fatty acid and a fatty acid salt in water. Compare the solubility of a fatty acid and a fatty acid s

alt in water. The salt is more soluble in water since it can form stronger ion-dipole interactions not available to the fatty acid. The fatty acid is more soluble in water since it can form stronger hydrogen bonding interactions not available to the fatty acid salt. The salt is more soluble in water since it can form stronger hydrogen bonding interactions not available to the fatty acid. The fatty acid is more soluble in water since it can form stronger ion-dipole interactions not available to the fatty acid salt.
Chemistry
1 answer:
anyanavicka [17]3 years ago
5 0

Answer:

The correct option is A. The salt is more soluble in water since it can form stronger ion-dipole interactions not available to the fatty acid.

Explanation:

An ion-dipole interaction occurs when an ionic compound is placed in a polar solvent. As salts are ionic compounds and water is a polar solvent, so the fatty acid salts will be able to form electrostatic ion-dipole interactions with the polar water molecules. These interactions will cause fatty acid salts to dissolve in water.

The fatty acid is not an ionic compound and will not form the ion-dipole interactions with the water molecules. Hence, fatty acids will be less soluble in water.

You might be interested in
Propose a 3-step reaction for the conversion of cyclopentene to propanedioic acid
Gnom [1K]

I
don't know because this is the question which I never heard

6 0
3 years ago
using the equation you wrote determine how many moles of butane c4h10 are needed to react with 5.5 moles of oxygen
GaryK [48]

Answer:

0.846 moles.

Explanation:

  • This is a stichiometric problem.
  • The balanced equation of complete combustion of butane is:

C₄H₁₀ + 6.5 O₂ → 4 CO₂ + 5 H₂O

  • It is clear from the stichiometry of the balanced equation that complete combustion of 1.0 mole of butane needs 6.5 moles of O₂ to produce 4 moles of CO₂ and 5 moles of H₂O.

<u><em>Using cross multiplication:</em></u>

  • 1.0 mole of C₄H₁₀ reacts with → 6.5 moles of O₂
  • ??? moles of C₄H₁₀ are needed to react with → 5.5 moles of O₂
  • The number of moles of C₄H₁₀ that are needed to react with 5.5 moles of O₂ = (1.0 x 5.5 moles of O₂) / (6.5 moles of O₂) = 0.846 moles.
3 0
3 years ago
Which probe should be used to check the temperature of a chicken breast?
Eddi Din [679]

Answer:

penetration probe

Explanation:

it is a penetration probe

8 0
2 years ago
A 7.27-gram sample of a compound is dissolved in 250. grams of benzene. The freezing point of this solution is 1.02°C below that
UkoKoshka [18]

Answer:

The correct answer is 146 g/mol

Explanation:

<em>Freezing point depression</em> is a colligative property related to the number of particles of solute dissolved in a solvent. It is given by:

ΔTf = Kf x m

Where ΔTf is the freezing point depression (in ºC), Kf is a constant for the solvent and m is the molality of solution. From the problem, we know the following data:

ΔTf = 1.02ºC

Kf = 5.12ºC/m

From this, we can calculate the molality:

m = ΔTf/Kf = 1.02ºC/(5.12ºC/m)= 0.199 m

The molality of a solution is defined as the moles of solute per kg of solvent. Thus, we can multiply the molality by the mass of solvent in kg (250 g= 0.25 kg) to obtain the moles of solute:

0.199 mol/kg benzene x 0.25 kg = 0.0498 moles solute

There are 0.0498 moles of solute dissolved in the solution. To calculate the molar mass of the solute, we divide the mass (7.27 g) into the moles:

molar mass = mass/mol = 7.27 g/(0.0498 mol) = 145.9 g/mol ≅ 146 g/mol

<em>Therefore, the molar mass of the compound is 146 g/mol </em>

6 0
3 years ago
I WILL GIVE BRAINIEST AND MORE !!
icang [17]
Composting is a technique that allows biodegradable materials of urban, domestic and industrial origin to be degraded to form humus, a type of soil that is very fertile and extremely rich in micronutrients.
These biodegradable materials are materials of organic origin, such as food scraps, fruit peels, pieces of vegetables, among others. As the domestic environment generates a large amount of organic waste, composting in this environment is very favorable, and it can generate a very rich soil to be used in the garden, in vegetables, among other places.


Hope this helps :)
3 0
2 years ago
Other questions:
  • Which of the following reactions is spontaneous?
    8·1 answer
  • What is true about energy
    15·1 answer
  • What element is found in liver and red blood cells and is needed to prevent anemia
    14·2 answers
  • Rita divides Avogadro’s number (approximately 6.02214 mc002-1.jpg 1023) by 2.055 to calculate the number of atoms in a sample. W
    6·2 answers
  • Determine the pressure change when a constant volume of gas at 1.00 atm is heated from 20C to 30C
    13·1 answer
  • What is meant by the statement "saturated hydrocarbons are relatively inert"?
    12·1 answer
  • Calculate the mass of sucrose needed to prepare a 2000 grams of 2.5% sucrose solution.
    7·1 answer
  • The volume of a sample of oxygen is 300.0 mL when the pressure is 1.00 atm and the temperature is 27.0°C. At what temperature is
    11·1 answer
  • An atom has the following electron configuration.
    10·1 answer
  • A solution is 0. 0480 m lif. What is the molarity of the solution if the density is 1. 10 g/ml?.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!