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adell [148]
3 years ago
12

Lines m and n are parallel solve for the following values of x. Tell which theorem you used.

Mathematics
1 answer:
nevsk [136]3 years ago
8 0

Answer:

x=60°

Step-by-step explanation:

angle 135° and (2x+15)° are corresponding and thus are equal

Therefore (2x+15)°=135°

2x=135-15

2x=120°

X=60°

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W^2 + 2 + 48 divided by 2z. If w = 5 and z = 8 *
Svetradugi [14.3K]

Replace w and z with the given values:

5^2 + 2 + 48 / 2(8)

Simplify:

75/16 = 4 and 11/16

8 0
3 years ago
-7 times what equals 2? i’ll give brainliest
lisov135 [29]

Answer:-3.5

Step-by-step explanation:

4 0
3 years ago
Can anyone help me!​
zhenek [66]

Answer:

\large \text{$ \sf 2^{-64}$}

Step-by-step explanation:

Given:

\large \text{$ \sf (256)^{-4^{\frac{3}{2}}}$}

This reads as:  256 to the power of "-4 to the power of 3/2".

Therefore, we need to deal with the "-4 to the power of 3/2" first.

Rewrite the 4 as 2²:

\large \text{$ \sf \implies -(2^2)^{\frac{3}{2}}$}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\large \text{$ \sf \implies -2^{\left(2 \times \frac{3}{2}\right)}$}

\large \text{$ \sf \implies -2^{3}$}

Therefore:

\large \text{$ \sf \implies -2^3=(-2)(-2)(-2) = -8$}

Replace "-4 to the power of 3/2" with -8 :

\large \text{$ \sf \implies 256^{-8}$}

Rewrite 256 as 2⁸ :

\large \text{$ \sf \implies (2^8)^{-8}$}

\textsf{Again, apply exponent rule} \quad (a^b)^c=a^{bc}:

\large \text{$ \sf \implies 2^{(8 \times -8)}$}

\large \text{$ \sf \implies 2^{-64}$}

In one complete calculation:

\large\begin{aligned} \sf (256)^{-4^{\frac{3}{2}}} & = \sf (256)^{-(2^2)^{\frac{3}{2}}}\\& = \sf (256)^{-2^{\left(2 \times \frac{3}{2}\right)}}\\& =\sf  (256)^{-2^{3}}\\& = \sf (256)^{-8}\\& \sf = (2^8)^{-8}\\& = \sf 2^{(8 \times -8)}\\& =\sf  2^{-64}\end{aligned}

Learn more about exponent rules here:

brainly.com/question/28211147

brainly.com/question/27959936

4 0
1 year ago
Read 2 more answers
ASAP HELP: If a sample proportion is 0.55, which range of possible values best describes an estimate for the population paramete
iris [78.8K]

Answer:

B.(0.4,0.7)

Step-by-step explanation:

We are given that

Sample proportion

\hat{p}=0.55

We have to find the range of possible values which   describes best  an estimate for the population parameter.

Estimate  for the population parameter

\hat{p}\pm Z(SE)

A.(0.55,0.6)

Difference between 0.55 and 0.55=0

Difference between 0.55 and 0.6=0.05

Difference between 0.55 and 0.55 is not equal to difference between 0.55 and 0.6.

Hence, option A is wrong.

B.(0.4,0.7)

Difference between 0.55 and 0.4=0.15

Difference between 0.55 and 0.7=0.15

Difference between 0.55 and 0.4 is equal to difference between 0.55 and 0.7.

Hence, option B is correct.

C. (0.4,0.69)

Difference between 0.55 and 0.4=0.15

Difference between 0.55 and 0.69=0.14

Difference between 0.55 and 0.4 is not equal to difference between 0.55 and 0.69.

Hence, option C is not correct.

D.(0.5,0.59)

Difference between 0.55 and 0.5=0.05

Difference between 0.55 and 0.59=0.04

Difference between 0.55 and 0.5 is not equal to difference between 0.55 and 0.59.

Hence, option D is not  correct.

5 0
3 years ago
If α and β are the zeroes of the polynomial ax^2 + bx + c, find the value of α^2 + β^2
Pie

Answer:

Step-by-step explanation:

α + β = -b/a

αβ = c/a

α² + β² = (α + β)² - 2αβ

           = (\frac{-b}{a})^{2}-2\frac{c}{a}\\\\= \frac{b^{2}}{a^{2}}-\frac{2c}{a}\\\\=\frac{b^{2}}{a^{2}}-\frac{2c*a}{a*a}\\\\=\frac{b^{2}-2ca}{a^{2}}

7 0
3 years ago
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