Answer:

Step-by-step explanation:
6 symbols and 4-symbol code so number of combinations wich doesn't contain the same symbol twice would be:
6•5•4•3 = 360
If code starts with a star followed by triangle that means only one posibility for first two symbols and code doesn't containing the same symbol twice means that left 4 symbols for next two.
So number of combinations of code starting with a star followed by triangle and doesn't containing the same symbol twice will be:
1•1•4•3 = 12
The probability that a randomly chosen code starts with a star followed by triangle and doesn't contain the same symbol twice:

She could put 6 stamps on 4 pages, and 9 stamps on the other pages
6 * 4 = 24
78 - 24 = 54
54/9= 6
F = 2.5p, where p is 1 large pizza
The first option
(X 3-y) (3+z)
That's the two polynomials
Answer:
The answer to your question is the first option
Step-by-step explanation:
Write the division
7x³ - 7x² + 6x +4 Result
x + 1 7x⁴ - 0x³ - 1x² + 10x + 15
-7x⁴ - 7x³
0 - 7x³ - 1x²
+ 7x³ +7x²
0 + 6x² + 10x
- 6x² - 6x
0 + 4x + 15
- 4x - 4
0 + 11 Remainder
Result = 7x³ - 7x² + 6x + 4 + 11 / x + 1