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4 years ago

For which data representation is the median the better measure of center

Mathematics

2 answers:

arlik [135]4 years ago

8 0

Answer: The second graph

In all but the 3 graphs, the data is perfectly symmetrical. This means that the mean and the median would be the same.

However, in the second graph the data is skewed to the right. This means that the mean would also be skewed to the right due to the larger scores there. Using the median in this case would give a clearer picture of the data.

katrin2010 [14]4 years ago

7 0

Answer:

Step-by-step explanation:

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lozanna [386]

Answer:

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Step-by-step explanation:

Sure... why not

3 0

3 years ago

Read 2 more answers

3. Jen’s parents buy a tablet for her to use in school. Of the $1500 cost, her parents expect her to pay back $1000 one year lat

NNADVOKAT [17]

Answer:

Step-by-step explanation:

Using the formula for calculating simple interest as shown;

Simple Interest = Principal * Rate *Time/100

Principal = Cost of tablet = $1500

Interest after one year = $1500-$1000 = $500

Time = 1year

Substituting this values into the formula;

$500 = 1500*rate*1/100\\Cross\ multiplying\\50,000 = 1500 * rate\\Rate = 50,000/1500\\Rate = 33.3%$

The interest rate that her parents assumed is 33.3%

4 0

3 years ago

Customers arrive at a service facility according to a Poisson process of rate λ customers/hour. Let X(t) be the number of custom

mash [69]

Answer:

Step-by-step explanation:

Given that:

X(t) = be the number of customers that have arrived up to time t.

$W_1,W_2$ ... = the successive arrival times of the customers.

(a)

Then; we can Determine the conditional mean E[W1|X(t)=2] as follows;

$E(W_!|X(t)=2) = \int\limits^t_0 {X} ( \dfrac{d}{dx}P(X(s) \geq 1 |X(t) =2))$

$= 1- P (X(s) \leq 0|X(t) = 2) \\ \\ = 1 - \dfrac{P(X(s) \leq 0 , X(t) =2) }{P(X(t) =2)}$

$= 1 - \dfrac{P(X(s) \leq 0 , 1 \leq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}$

$= 1 - \dfrac{P(X(s) \leq 0 ,P((3 \eq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}$

Now $P(X(s) \leq 0) = P(X(s) = 0)$

(b) We can Determine the conditional mean E[W3|X(t)=5] as follows;

$E(W_1|X(t) =2 ) = \int\limits^t_0 X (\dfrac{d}{dx}P(X(s) \geq 3 |X(t) =5 )) \\ \\ = 1- P (X(s) \leq 2 | X (t) = 5 ) \\ \\ = 1 - \dfrac{P (X(s) \leq 2, X(t) = 5 }{P(X(t) = 5)} \\ \\ = 1 - \dfrac{P (X(s) \LEQ 2, 3 (t) - X(s) \leq 5 )}{P(X(t) = 2)}$

Now; $P (X(s) \leq 2 ) = P(X(s) = 0 ) + P(X(s) = 1) + P(X(s) = 2)$

So ; the conditional probability density function of $W_2$ given that X(t)=5 is:

$f_{W_2|X(t)=5}}= (W_2|X(t) = 5) \\ \\ =\dfrac{d}{ds}P(W_2 \leq s | X(t) =5 ) \\ \\ = \dfrac{d}{ds}P(X(s) \geq 2 | X(t) = 5)$

7 0

3 years ago

What is 2/3 + 3/4 + 5/6 + 4/8 + 3/12 + 3/2

Stella [2.4K]

Answer:

9/2

Step-by-step explanation:

2/3 + 3/4 + 5/6 + 4/8 + 3/12 + 3/2 =

= 16/24 + 18/24 + 20/24 + 12/24 + 6/24 + 36/24

= 108/24

= 54/12

= 9/2

3 0

3 years ago

What are the answers for the chart in number 4,5,6

svetoff [14.1K]

#4(1)=-1. (2)=5. (3)=14. (4)=26 srry but all i know hoped i helped

[how i did]

the first one i did 3×-5+14 which equals -1
and the second one is the same two 3×-3+14=5 you just add the the number on B

7 0

3 years ago