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poizon [28]
3 years ago
5

PLs come answer this please this is another one

Mathematics
2 answers:
adell [148]3 years ago
5 0

Answer:

......

Step-by-step explanation:

crimeas [40]3 years ago
3 0
Number 6 is b and number 7 is c
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Sherri’s trellis is shown.
Eddi Din [679]

Answer:

A and C

Step-by-step explanation:

4 0
3 years ago
HELP ASAP. solve for x
Amanda [17]

Answer:

x = 25

Step-by-step explanation:

The triangle is isosceles, therefore, the base angles are the same

62 + 2x + 9 + 2x + 9 = 180

62 + 4x + 18 = 180

4x = 180 - 62 - 18

4x = 100

x = 100/4

x = 25

5 0
3 years ago
The sum of three consecutive even numbers is 438. What is the 2nd number?
denis-greek [22]

First number = x

Second number = x + 2

Third number = x + 4

X + x +2 + x + 4 = 438

Simplify:

3x + 6 = 438

Subtract 3 from both sides

3x = 432

Divide both sides by 3

X = 144

The second number is 144 + 2 = 146

4 0
4 years ago
Evaluate ∫ xe2x dx. 1 2 3x A./xe +C 6 B.1/xe2x-1/ xe2x+C 22 C.1/xe2x-1/ e2x+C 24 1 2 1 4x D./x-/e +C 28
Dafna1 [17]
The answer is (1/2)xe^(2x) - (1/4)e^(2x) + C

Solution:
Since our given integrand is the product of the functions x and e^(2x), we can use the formula for integration by parts by choosing
     u = x
     dv/dx = e^(2x)

By differentiating u, we get
     du/dx= 1
By integrating dv/dx= e^(2x), we have
     v =∫e^(2x) dx = (1/2)e^(2x)

Then we substitute these values to the integration by parts formula:
     ∫ u(dv/dx) dx = uv −∫ v(du/dx) dx 
     ∫ x e^(2x) dx = (x) (1/2)e^(2x) - ∫ ((1/2) e^(2x)) (1) dx
                          = (1/2)xe^(2x) - (1/2)∫[e^(2x)] dx
                          = (1/2)xe^(2x) - (1/2) (1/2)e^(2x) + C
where c is the constant of integration.

Therefore, 
     ∫ x e^(2x) dx = (1/2)xe^(2x) - (1/4)e^(2x) + C
7 0
4 years ago
state is the triangles in each pair are similar. If so, say how you know they are similar and complete the similarity statement​
lina2011 [118]

Answer:

1st

Step-by-step explanation:

The two triangles are similar by AA

Firstly, we can see that angle LKM and QKR are congruent as they are vertical angles.

The second set can be identified by noticing that RM is a transversal through 2 parrallel lines LM and QR. That manes QRK, and LMK alternate interior angles, showing that the angles are congruent. Hence similarity by AA

3 0
3 years ago
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