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sasho [114]
3 years ago
7

How do I graph this.

Mathematics
1 answer:
kykrilka [37]3 years ago
5 0

bad cropping, but there it is. i suggest using an app called photo math if youre having trouble. it shows you the step by step process

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Find the lateral area of a rectangluar prism with ?
NikAS [45]

Answer:

40 Squared units

Step-by-step explanation:

A=2*2*4+2*2*6=40

4 0
3 years ago
Unit rate feet per second 180 miles over 2 hours
Tatiana [17]
So that is equal to 180 miles per 2 hours which is 90 miles per hour if each hour has the same m/hr rate.
You can set up a proportion:
let x = number of miles per hour
\frac{x}{180} = \frac{1}{2}
cross multiply and you get
2x=180
divide both sides by 2 and you get
x=90
so you get the same answer both ways,
90 miles per hour
5 0
3 years ago
Dale finished his English assignment in 1/3 hours . Then he completed his chemistry assignment in 1/2 hours . How much more time
11Alexandr11 [23.1K]

Answer:

1/6 hours

Step-by-step explanation:

Since it wants a fraction form all you have to do is subract 1/3 from 1/2

1/2 - 1/3

cross multiply:

3/2-2/3

subtract the numerator but multiply the denominator and simplify if you have to:

1/6

6 0
3 years ago
Please help solve the ineaquality x over 3 is < than 3
elena55 [62]
We have an inequation: 
x/3 < 3
⇒ x < 3*3
⇒ x < 9

The final answer is x < 9~
7 0
3 years ago
A child lets go of a balloon that rises at a constant rate. 5 seconds after it was released, the balloon is at a height of 16 fe
Mama L [17]

Answer:

1. h = 2.4t + 4

2. 4 feet

3. 220 feet

Step-by-step explanation:

1. Write a linear model for the height, h, of the balloon as a function of the number of seconds, s that it has been raising.

Since the balloon rises at a constant rate, we find this rate by using the initial and final values of height and time at 5 seconds and 20 seconds respectively which are 12 feet and 52 feet respectively.

So, rate = gradient of line

= change in height/change  in time

= (52 ft - 16 ft)/(20 s - 5 s)

= 36 ft/15 s

= 2.4 ft/s

Now the equation of the line which shows the height is gotten from

(h - h')/(t - t') = rate

Using h'= 16 feet and t' = 5 s, we have

(h - 16)/(t - 5) = 2.4

h - 16 = 2.4(t - 5)

h - 16 = 2.4t - 12

h = 2.4t - 12 + 16

h = 2.4t + 4

where h is the height of the balloon above the ground and t is the time spent in the air in seconds.

2. What was the height of the balloon initially before the child let it go?

We obtain the initial height of the balloon before the child let go at time, t = 0 the time before the child let go.

So, substituting t = 0 into the equation for h, we have

h = 2.4t + 4

h = 2.4(0) + 4

h = 0 + 4

h = 4 feet

So, the height of the balloon before the child let go is 4 feet above the ground.

3. Use your model to predict the height of the balloon after 90 seconds.

We insert t = 90 s into the equation for h. So,

h = 2.4t + 4

h = 2.4(90) + 4

h = 216 + 4

h = 220 feet

So, the height of the balloon after 90 s is 220 feet above the ground.

8 0
3 years ago
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