All categories

3 years ago

PLEASE GEOMETRY HELP WILL MARK BRAINLIEST!!!

Mathematics

2 answers:

PIT_PIT [208]3 years ago

7 0

Answer:

m<BAD = 67

Step-by-step explanation:

The given figure is a parallelogram. Consecutive angles in a parallelogram are supplementary, meaning that their angle measures sum up to 180 degrees. Using this, one can say,

m<D + m<A = 180

Substitute,

m<ADB + m<BDC + m<A = 180

71 + 42 + m<A = 180

113 + m<A = 180

Inverse operations,

113 + m<A = 180

-113 -113

m<A = 67

Reika [66]3 years ago

5 0

Answer:

Step-by-step explanation:

71+42+BAD=180

BAD=67

You might be interested in

Plz help me due today

brilliants [131]

Answer:

Plan A: Geometric function

Plan B: Arithmetic function

Monday

10, 30

Tuesday

20, 40

Wednesday

40, 50

Thursday

80, 60

Friday

160, 70

6 0

3 years ago

I don't understand these, please help!

den301095 [7]

Step-by-step explanation:

x=1 y=3

x=4 y=0

y=mx+b

3=m+b

0=4m+b

3=-3m

m= -1

0=-4+b

b=4

y= -x +4

x=2 y=0

x=0 y= -4

0=2m+b

-4=b

b=-4

0=2m-4

2m=4

m=2

y=2x-4

3 0

3 years ago

Read 2 more answers

A regular decagon has a radius of 14'. Determine the length of the apothem. Then determine the perimeter of the decagon

pav-90 [236]

Answer:

Part 1) The length of the apothem is 13.32'

Part 2) The perimeter of the decagon is 86.5'

Step-by-step explanation:

we know that

A regular decagon has 10 equal sides and 10 equal interior angles

A regular decagon can be divided into 10 congruent isosceles triangle

(they are isosceles since their two sides are the radii of the polygon and the unknown side is the side of the polygon)

The vertex angle of each isosceles triangle is equal to

$\frac{360^o}{10}=36^o$

To find out the side length of the decagon, we can use the law of cosines

$c^2=a^2+b^2-2(a)(b)cos(C)$

where

c is the length side of decagon

a and b are the radii

we have

$a=14'\\b=14'\\C=36^o$

substitute the values

$c^2=14^2+14^2-2(14)(14)cos(36^o)$

$c^2=392-(392)cos(36^o)$

$c=8.65'$

To fin out the perimeter of decagon multiply the length side by 10

$P=8.65(10)=86.5'$

To find out the apothem we can apply the Pythagorean Theorem in one isosceles triangle

see the attached figure to better understand the problem

$r^2=a^2+(c/2)^2$

substitute the given values

$14^2=a^2+(8.65/2)^2$

solve for a

$a^2=14^2-(8.65/2)^2$

$a=13.32'$

8 0

3 years ago

The square below represents a unit or a whole. What fraction is represented by the

Mkey [24]

20/28 or 10/14 or 5/7
You can keep reducing until both sides of the fraction can't be divided by the same number anymore.

5 0

3 years ago

Please i need help please help me out!

TiliK225 [7]

Answer:

1. 13 or -13

2. -5 < y < -3

3. 6 or -6

4. 1/8 or -1/8

Step-by-step explanation:

Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.

The Absolute Value term is |x|

For the Negative case we'll use -(x)

For the Positive case we'll use (x)

Step 3 :

Solve the Negative Case

-(x) = 13

Multiply

-x = 13

Multiply both sides by (-1)

x = -13

Which is the solution for the Negative Case

Step 4 :

Solve the Positive Case

(x) = 13

Which is the solution for the Positive Case

Step 5 :

Wrap up the solution

x=-13

x=13

But for the case of question (2) its a different pattern..

Since this is a "less than" absolute-value inequality, my first step is to clear the absolute value according to the "less than" pattern. Then I'll solve the linear inequality.

| y + 4 | < 1

–1 < y + 4 < 1

This is the pattern for "less than". Continuing, I'll subtract 3 from all three "sides" of the inequality:

–1 – 4 < y + 4 - 4 < 1 – 4

–5 < y < -3

$- 5 < y < - 3$

The solution to the original absolute-value inequality, | y + 4 | < 1 , is the interval:

$- 5 < y < - 3$

7 0

3 years ago