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Rainbow [258]
3 years ago
13

Find the nth term of the following sequence: 5, 8, 13, 20, 29, ...

Mathematics
1 answer:
Tems11 [23]3 years ago
6 0

Answer:

85

Step-by-step explanation:

The number you Add with goes up by 2 with each equation. Since five is the first number,

5+3=8 (Pattern #2)

8+5=13 (Pattern #3)

13+7=20 (pattern #4)

20+9=29 (pattern #5)

29+11=40 (pattern #6)

40+13= 53 (pattern #7)

53+15=68 (pattern #8)

68+17=85 (pattern #9)

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Answer:

Step-by-step explanation:

i 798

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An exercise machine with an original selling price of $1225 is marked down by 20%. What is the sale price of the exercise​ machi
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Write 0.216 as a rational number in lowest terms
lozanna [386]

Answer:

=\frac{27}{125}

Step-by-step explanation:

0.216

\mathrm{Multiply\:and\:divide\:by\:10\:for\:every\:number\:after\:the\:decimal\:point.}

\mathrm{There\:are\:}3\mathrm{\:digits\:to\:the\:right\:of\:the\:decimal\:point,\:therefore\:multiply\:and\:divide\:by\:}1000

=\frac{0.216\cdot \:1000}{1000}

=\frac{216}{1000}

216,\:1000

\mathrm{The\:GCD\:of\:}a,\:b\mathrm{\:is\:the\:largest\:positive\:number\:that\:divides\:both\:}a\mathrm{\:and\:}b\mathrm{\:without\:a\:remainder}

2,\:3\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:2\cdot \:3\cdot \:3\cdot \:3

2,\:5\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:2\cdot \:5\cdot \:5\cdot \:5

\mathrm{The\:prime\:factors\:common\:to\:}216,\:1000\mathrm{\:are\:}

=2\cdot \:2\cdot \:2

\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2\cdot \:2=8

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\mathrm{Cancel\:the\:common\:factor:}\:8

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Hence, the correct answer is =\frac{27}{125}

6 0
3 years ago
What is 50 percent of 18?
Effectus [21]
Steps:
18*0.5=9

Answer:

9
3 0
2 years ago
Read 2 more answers
Please help with 6 and 7
Maru [420]

Answer:

6a) i- 2hrs 36mins  ii- 3hrs 12mins

b) car A≈ 76.9km/h  car B≈ 62.5km/h

c)------

7a) 35km

b) car A=75km  car B=60km

c) 30km

d) car A≈36mins  car B≈48mins

Step-by-step explanation:

6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.

b) Using the answer from a, you divide 200km by the time.

For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6

∴ car A: 200/2.6≈ 76.92km/h

For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2

∴ car B: 200/3.2≈ 62.5km/h

7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.

b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).

c) Difference from car A line to car B:

155km-125km=30km

d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.

Hope this helps.

5 0
4 years ago
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