Hello!
For this you can plug in the x values in the choices and see if you get the y value
y =
![-4^{3} - (-4)](https://tex.z-dn.net/?f=%20-4%5E%7B3%7D%20%20-%20%28-4%29)
-4^3 is -64
when you subtract a negative you are just adding
-64 + 4 = 60
Then you do the second one
![y = -3^{3} - (-3)](https://tex.z-dn.net/?f=y%20%3D%20%20-3%5E%7B3%7D%20%20-%20%28-3%29)
-3^3 is -27
-27 + 3 is -24
Then the third one
![y = -2^{3} - (-2)](https://tex.z-dn.net/?f=y%20%3D%20%20-2%5E%7B3%7D%20%20-%20%28-2%29)
-2^3 is -8
-8 + 2 is -6
Then the last one
![y = -1^{3} - (-1)](https://tex.z-dn.net/?f=y%20%3D%20%20-1%5E%7B3%7D%20%20-%20%28-1%29)
-1^3 is -1
-1 + 1 = 0
Since we did not get -2 the answer is D
Hope this Helps!
Answer:
a and b
Step-by-step explanation:
Answer:
143.6
Step-by-step explanation: i swear its right
Answer:
Daeja is correct.
Step-by-step explanation:
Equation: 6 = 1/2s
Solve:
(2)6 = 1/2s(2) <== multiply both sides by 2
12 = s or s = 12
Therefore, Daeja is correct.
I multiplied both sides by 2 to isolate s, and 2 ⋅ 6 is 12.
Hope this helps!