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ss7ja [257]
3 years ago
5

If I had a literal equation that was 1/2f + i = h, what would "i" equal in this equation?

Mathematics
1 answer:
Anni [7]3 years ago
7 0

Answer:

i = h + \frac{1}{2f}

Step-by-step explanation:

\frac{1}{2f} + i = h

Taking \frac{1}{2f} to the other side, you have:

i = h + \frac{1}{2f}

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12x+5y3z, where ​x=12​, y = 6, and z = 3
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4 0
3 years ago
The upper arm length of females over 20 years old in a country is approximately Normal with mean 35.8 centimeters (cm) and stand
lana [24]

Answer:

a) The range of lengths from 28.3 cm to 43.3 cm covers almost all (99.7%) of this distribution.

b) 16% of women over 20 have upper arm lengths less than 33.3 cm.

Step-by-step explanation:

The Empirical Rule(68-95-99.7 Rule) states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 35.8 cm

Standard deviation = 2.5 cm

(a) What range of lengths covers almost all (99.7%) of this distribution?

This range is from 3 standard deviations below the mean to three standard deviations above the mean.

So from 35.8 - 3*2.5 = 28.3 cm to 35.8 + 3*2.5 = 43.3 cm

The range of lengths from 28.3 cm to 43.3 cm covers almost all (99.7%) of this distribution.

(b) What percent of women over 20 have upper arm lengths less than 33.3 cm?

68% of the women over 20 have upper arm length between 33.3 cm and 38.3 cm. The other 32% have upper arm length lower than 33.3 cm or higher than 38.3. The distribution is symmetric, so 16% of the have upper arm length lower than 33.3 cm and 16% have upper arm length higher than 38.3 cm

So 16% of women over 20 have upper arm lengths less than 33.3 cm.

4 0
3 years ago
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