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3 years ago

How to solve this equation?

Mathematics

2 answers:

mafiozo [28]3 years ago

4 0

$\bf 5(x-5)^2-9=6\implies 5(x-5)^2=15\implies (x-5)^2=\cfrac{15}{5}\implies (x-5)^2=3 \\\\\\ \sqrt{(x-5)^2}=\sqrt{3}\implies x-5=\sqrt{3}\implies x=\sqrt{3}+5$

pochemuha3 years ago

3 0

Answer:

Take it slowly

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

Can anyone explain step by step how to get this answer? Will mark branliest!!

Y_Kistochka [10]

Answer:

Step-by-step explanation:

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2 years ago

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Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,

Sholpan [36]

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We can conclude that the distance between my house and the movie theater is $\sqrt{13}$

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This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
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$d= \sqrt{61}$
We can conclude that the distance between the police station and the airport is $\sqrt{61}$

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$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance from the park to the Fire Station is $\sqrt{10}$

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$d^2=2^2+1^2$
$d^2=4+1$
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D. What is the distance between your house and the mall?
Answer:
$d^2=4^2+4^2$
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What is the distance between the movie theater and the school?
answer:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance between the movie theater and the school is $\sqrt{10}$

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2 years ago

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hram777 [196]

Answer:

Hello! I think the answer is D: $2.25. Please correct me if i'm wrong.

Step-by-step explanation:

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2 years ago

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