3 years ago

WILL GIVE BRAINLIEST! BEING TIMED PRE-CALC

Mathematics

1 answer:

ycow [4]3 years ago

5 0

It’s 0

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denis-greek [22]

Answer:

Part a) $AB=15\ cm$

Part b) $AB=11.1\ cm$

Part c) $AB=3/5\ cm$

Part d) $AB=3s\ cm$

Step-by-step explanation:

see the attached figure to better understand the question

we know that

To find the length of the image after a dilation, multiply the length of the pre-image by the scale factor

Part a) we have

The scale factor is 5

The length of the pre-image is 3 cm

therefore

The length of the image AB after dilation is

$3(5)=15\ cm$

Part b) we have

The scale factor is 3.7

The length of the pre-image is 3 cm

therefore

The length of the image AB after dilation is

$3(3.7)=11.1\ cm$

Part c) we have

The scale factor is 1/5

The length of the pre-image is 3 cm

therefore

The length of the image AB after dilation is

$3(1/5)=3/5\ cm$

Part d) we have

The scale factor is s

The length of the pre-image is 3 cm

therefore

The length of the image AB after dilation is

$3(s)=3s\ cm$

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3 years ago

What is the slope of the line containing(-3,5) and (6,-1)

GaryK [48]

$\frac{5 - (-1)}{-3-6} = \frac{6}{-9} = \frac{2}{-3} = -0.6666$

slope = -0.6666

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Let f(x) =x+1 and g(x)=1/x. The graph of (f o g)(x) is shown below. What is the range of (f o g)(x)?

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Looks like all real numbers except 1. It touch's all the y except 1 aka range

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The new number, 550, is 200 more than the original number. What is the approximate percent change?a The percent change is 33%. b

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B The percentage change is 55%

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If sin θ=4/5 and 90°<θ<180°, what is cos θ?

34kurt

Answer:

Cos ∅ = 3/5

BUT COSINE IS NEGATIVE IN THE SECOND QUADRANT.

Thus cos∅= -3/5

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3 years ago