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harina [27]
2 years ago
8

IF Triangle DEF JKL, find KL.

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
3 0

Answer:

b

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

\frac{KL}{EF} = \frac{JK}{DE} , substitute values

\frac{6x+3}{x+11} = \frac{25}{10} ( cross- multiply )

10(6x + 3) = 25(x + 11) ← distribute parenthesis on both sides

60x + 30 = 25x + 275 ( subtract 25x from both sides )

35x + 30 = 275 ( subtract 30 from both sides )

35x = 245 ( divide both sides by 35 )

x = 7

Then

KL = 6x + 3 = 6(7) + 3 = 42 + 3 = 45 → b

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Step-by-step explanation:

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b) . Use composition to show that f(x) and g(x) are inverses of each other.

\mathrm{For}\:f=\frac{2}{5}x-4\:\\\\\mathrm{substitute}\:x\:\mathrm{with}\:g\left(x\right)=\frac{5}{2}x+10\\\\=\frac{2}{5}\left(\frac{5}{2}x+10\right)-4\\\\=x

Similarly,

\mathrm{g\left(x\right)=\frac{5}{2}x+10,\:f\left(x\right)=\frac{2}{5}x-4,\:g\left(x\right)\circ \:f\left(x\right)}\\\\\mathrm{For}\:g=\frac{5}{2}x+10\:\mathrm{substitute}\:x\:\mathrm{with}\:f\left(x\right)=\frac{2}{5}x-4\\\\=\frac{5}{2}\left(\frac{2}{5}x-4\right)+10\\\\=x

so, both are inverses of each other.

c) Draw the graphs of f(x) and g(x) on the same coordinate plane.

As shown below in the graph , Since for inverse function we need an axis of symmetry i.e. y=x

And both f(x) and g(x) are symmetry to y=x.

∴ f(x) and g(x) are inverses of each other.


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