Answer:
m < EAD = 29 degrees
m < CAB = 119 degrees
Given :
The question states that m < CAE = m<FAB = 61 degrees and m<DAF = 90 degrees
Solution:
1. Since line CAF and EAB intersect each other, m<CAF = m< EAF - (opposite vertical angles are equivalent)
2. m<BAC + m<EAC = 180 degrees (sum of linear pair)
3. m<CAB = 180 degrees - m<EAC
4. Equation 1: m<CAB = m<EAF = 119 degrees
5. m<EAF = m<EAD + m< DAF
6. m<EAD = m<EAF - m<DAF
7. m<EAD = 119 degrees-90 degrees = 29 degrees
Hope this helps!!! :)
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Answer:
67.5°, 107.5°
Step-by-step explanation:
For supplementary angles, their sum equals 180°.
Let x be the first angle and y be the second angle, then
x + y = 180°.
It is given that x = y + 45°.
So x + y = 180°
substituting x into the equation, we have
y + 45° + y = 180°
simplifying, we have
2y + 45° = 180°
collecting like terms, we have
2y = 180° - 45°
2y = 135°
dividing through by 2, we have
y = 135°/2
y = 67.5°
Since y = 67.5°
then x = y + 45°
x = 67.5° + 45°
x = 107.5°
Answer:
6,271
Step-by-step explanation:
For x = 20 days: f(20) = 33(1.3)^20 = 33(190.0496377) = 6,271