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3 years ago

Which of the following explains the role of Pi (1) in finding the circumference of a circle?

Mathematics

1 answer:

scoundrel [369]3 years ago

4 0

Answer:

The answer is C, The use of Pi can be used to find the ratio of the diameter and circumference of a circle

Step-by-step explanation:

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Solve and explain please.

deff fn [24]

Are you still doing it.?

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3 years ago

Twenty six thousandths in numerical form

Andrew [12]

Answer:

0.026

Step-by-step explanation:

Twenty-Six = 26 ( But for simplicity in the Next Step write it as 26.)

Tenths means to move the Decimal Point 1 Place Left
Hundredths means to move the Decimal Point 2 Place Left
Thousandths means to move the Decimal Point 3 Place Left

Then Twenty-Six Thousandths = 0.026

8 0

2 years ago

Read 2 more answers

Maria has $28 to spend on bottles of water Each bottle of water costs $1.29. There is a $1.50 recycling fee for buying bottled w

Inessa05 [86]

28.150=26.5 is the amount you can spend on water. so 26.5/1.29= 20.54 so you can buy 20 bottles of water

4 0

3 years ago

Please help me thanks

posledela

Answer:

I knwo you Ur Gae

Step-by-step explanation:

6 0

3 years ago

Expand the binomial<br> <img src="https://tex.z-dn.net/?f=%28x-%5Cfrac%7B2%7D%7B5%7D%29%5E%7B2%7D" id="TexFormula1" title="(x-\f

kkurt [141]

Answer:

$(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}$

Step-by-step explanation:

You have two methods to expand this binomial.

Method 1

If you have the expression:

$(x- \frac{2}{5})^{2}$

You can write the expression it in the following way:

$(x-\frac{2}{5})^{2}=(x-\frac{2}{5})(x-\frac{2}{5})$

Then, apply the distributive property:

$(x-\frac{2}{5})(x-\frac{2}{5}) = x^2 -\frac{2}{5}x -\frac{2}{5}x+ (\frac{2}{5})\frac{2}{5}$

Simplify the expression:

$(x-\frac{2}{5})^2= x^2 -\frac{4}{5}x+ (\frac{4}{25})$

---------------------------------------------------------------------------------------

Method 2

For any expression of the form:

$(a-b)^2$

Its expanded form will be:

$(a-b)^2= a^2 -2ab + b^2$

$a = x$

$b =\frac{2}{5}$

$(x- \frac{2}{5})^{2} = x^2 - 2x\frac{2}{5} + (\frac{2}{5})^2$

$(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}$

3 0

3 years ago