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Kaylis [27]
2 years ago
12

I need help ASAP please help! 10th grade algebra

Mathematics
1 answer:
Sholpan [36]2 years ago
5 0
This is 10th grade I’m in regular 8th and can do this w no problem
You might be interested in
Could someone please help? They don’t need to be solved I just need help with the translating.
Lorico [155]

Answer:

I won't solve i'll translate like you asked

Step-by-step explanation:

13) x - 5 = 21

14) 12 × y = 48

15) b + 10 = 13

If you want I can solve.

HOPE THIS HELPED

5 0
3 years ago
Evaluate the following division: (3b-6a)÷(30a-15b)​
shutvik [7]

Evaluate the following division: (3b-6a)÷(30a-15b) is <u>-</u><u>1</u><u>/</u><u>5</u><u>.</u>

<h2><u>INTRODUCTION</u></h2>

~ Algebraic Forms and their Elements

Algebraic form is a mathematical form whose presentation involves symbols or letters to represent unknown numbers.

Elements of Algebra:

1. Variables, Constants and Coefficients

Pay attention to the algebraic form 3x + 2y + 3

From the algebraic form above, x and y are variables (variables), while the number 3 is a constant. A variable is a substitute symbol for a number whose value is not clearly known. While constants are terms of an algebraic form in the form of numbers and do not contain variables.

And what is meant by the coefficient is the constant factor of a term in algebraic form. The coefficient on the 3x term is 3, on the 2y term it is 2.

2. Terms and Factors

» The term is part of the algebraic form which is limited by the operation of addition (+) or difference (-). The term one is an algebraic form that is not connected by the operation of addition or difference.

Example: 2x, 2a², -4xy, . . .

» Term two is an algebraic form that is connected by an operation of sum or difference.

Example: 2x + 3, a² - 4, 3x² - 4x, . . .

» Similar terms in algebraic form are terms that have the same variable and the same power.

Example:

2a is similar to 3a, 4a, etc.

» Factors are part of the algebraic form that is restricted to multiplication operations.

Example: 5n = 5 × n, 5 and n are factors of 4n, respectively.

Calculation Operations on Algebraic Forms

1. Addition and subtraction of algebraic forms can only be done on similar terms.

2. Multiplication and division of algebraic forms.

Multiply two terms by constants or variables.

Example:

3 (4y + 5)

= (3 × 4y) + (3 × 5)

= 12y + 15

Division of two terms with a variable or constant, for example:

(8y+4)/2 = 8y/2 + 4/2 = 4y + 2

<h2><u>DISCUSSION</u></h2>

(3b-6a)÷(30a-15b)

= (-6a + 3b) ÷ (-5(-6a+3b))

= (-6a+3b)/(-5(-6a+3b))

= -1/5

<h3>Conclusion:</h3>

So, Evaluate the following division: (3b-6a)÷(30a-15b) is -1/5.

<h3>Learn More:</h3>

(mampir ke indo:v)

  1. Algebraic subtraction material: https://brainly.co.id/task/35216852
  2. Algebraic arithmetic operations: https://brainly.co.id/task/26250852
  3. The equation of the value of x in algebraic form: https://brainly.co.id/task/42124780

_____________

<h3>Answer Details:</h3>

Class: 7 Middle School

Subject: Math

Material: Chapter 2.1 -Operations of Algebraic Forms

Categorization Code: 7.2.2.1

Keywords: Simple form of algebra

7 0
2 years ago
Solve his problem for X and Y​
Verizon [17]

<em><u>Answer:</u></em>

<em><u>y = 5, 3; x = 171, 155</u></em>

<em><u>Step-by-step explanation:</u></em>

8y - 15 = y^2

y^2-8y+15=0

y^2-3y-5y+15=0

y(y-3)-5(y-3)=0

(y-5)(y-3)=0

y can be 5 or 3.

x = 180 - (8y - 15)

x = 180 - (8(3)-15)

x = 180 - 9

x = 171

OR

x = 180 - (8(5) - 15)

x = 180 - 25

x = 155

7 0
2 years ago
How many solutions does the following system of equations have? y=5/2x+2 and 2y=5x+8
Yuki888 [10]

Answer:

No solutions.

Step-by-step explanation:

y = 5/2x + 2

2y = 5x + 8

Plug the first equation into the second.

2(5/2x + 2) = 5x +8

5x + 4 = 5x + 8

<em>5x + 4 cannot equal 5x + 8, so this system of equations has no solutions.</em>

3 0
3 years ago
The display provided from technology available below results from using data for a smartphone carrier's data speeds at airports
harkovskaia [24]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the T test output :

T-Test

μ<4.00

t=-3.033077

p=0.002025

x=3.48

Sx=1.150075

n=45

Given that population mean, μ = 6

Confidence level, α = 0.05

The hypothesis :

H0 : μ = 6.00

H1 : μ < 6.00

From the t test output given :

The test statistic :

T = -3.033077

T = - 3.03 (2 decimal places)

The Pvalue :

P = 0.002025

Pvalue = 0.002 (3 decimal places)

The conclusion :

Decision region ; Reject H0 : if Pvalue < α

Since ; Pvalue < α

Reject H0 ; There is sufficient evidence to support claim that sample is from a population with a mean less than 6.

4 0
2 years ago
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