<span>6^1/3 * 6^1/4 = 6^x/y
The key to solving this problem is understanding properties of exponents:
If you are multiplying two powers with the same base (in this case the base is 6), the result is the base raised to the power of the two exponents added together.
6^1/3+1/4 = 6^x/y
6^7/12 = 6^x/y
So the product would be 6^7/12
x = 7
y = 12</span>
Answer:
A. y=3x but 3 is the slope
hope this helps
have a good day :)
Step-by-step explanation:
Let

be the length of the rectangle and

be the width. In the problem it is given that

. It is also given that the area

. Substituting in the length in terms of width, we have

. Using the zero product property,

. Solving these we get the width

. However, it doesn't make sense for the width to be negative, so the width must be

. From that we can tell the length

.
Answer:
<h2>Sorry mate I am not able to understand ur question ❓❓❓❓ . sorry mate next time I can give u the answer.</h2>
Could u give the rest of the question?