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OLga [1]
2 years ago
10

21 and 22 are complementary angles. The measure of Z1 is 45 The measure of Z2 is 3x°. Find the value of x. The figure is not dra

wn to scale​
Mathematics
1 answer:
Alex2 years ago
6 0

9514 1404 393

Answer:

  x = 15

Step-by-step explanation:

<u>Given</u>:

  ∠1 + ∠2 = 90°

  ∠1 = 45°

  ∠2 = 3x°

<u>Find</u>:

  x

<u>Solution</u>:

  Using the given values in the given equation, we have ...

  45° +3x° = 90°

  15 + x = 30 . . . . . . divide by 3°

  x = 15 . . . . . . . . . . . subtract 15

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Question is on picture attached
nalin [4]

7(\frac{9}{4}x- \frac{18}{7})= -\frac{5}{21} +\frac{17}{7}x   \frac{63}{4}x-18 =-\frac{5}{21}+ \frac{17}{7}x\\ \frac{63}{4}x -  \frac{17}{7}x = 18-\frac{5}{21}\frac{373}{28} =\frac{373}{21} x=\frac{4}{3}

ok done. Thank to me :>

5 0
2 years ago
Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL
Mice21 [21]

Answer:

KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM  

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}

Also

m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ} (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

NL=45\tan 50^{\circ}

m\angle KLN=m\angle LNM=40^{\circ} (alternate interior angles)

m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ} (angles KNL and KLN are complementary).

So,

\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08

and

\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47

3 0
3 years ago
Read 2 more answers
2x^3-3x^2-11x+6 divide by x-3
Alexxx [7]

Answer: 2x^2+3x-2

Step-by-step explanation:

You can do long division, which is very very hard to show with typing on a keyboard. You essentially want to divide the leading coefficient for each term. Ill try my best to explain it.

Do \frac{2x^3}{x}=2x^2. Write 2x^2 down. Now multiply (x - 3) by it. Then subtract it from the trinomial.

2x^2*(x-3)=2x^3 -6x^2\\(2x^3 -3x^2-11x+6)-(2x^3-6x^2) = 3x^2-11x+6

Now do \frac{3x^2}{x} =3x. Write that down next to your 2x^2. Multiply 3x by (x - 3) to get:

3x(x-3)=3x^2-9x\\(3x^2-11x+6)-(3x^2-9x)=-2x+6

Your final step is to do \frac{-2x}{x} =-2. Write this -2 next to your other two parts

Multiply -2 by (x - 3) to get:

-2(x-3)=-2x+6\\(-2x+6)-(-2x+6)=0

Our remainder is 0 so that means (x - 3) goes into that trinomial exactly:

2x^2+3x-2 times

4 0
2 years ago
Read 2 more answers
PLEASE HELP!!!30 POINTS
Tanzania [10]

Answer:

I Think Its C

Sorry if its wrong. Hope it helps...

4 0
2 years ago
True or False <br> No links
AlladinOne [14]

Answer:

False

<em>Brainliest, please!</em>

Step-by-step explanation:

+ + = +

- - = +

+ - = -

- + = -

7 0
3 years ago
Read 2 more answers
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