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AleksAgata [21]
4 years ago
12

Bags of 10 sold 2430 apples one day

Mathematics
1 answer:
Butoxors [25]4 years ago
7 0
If I am interpreting your question (which you did not ask), you want to know how many bags were sold.

2430/10 = 243 bags with 10 apples in each bag were sold.
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Given that S = TR and OP = 10, find the diameter of OT. Round the answer to the hundredths place.
Sonbull [250]
The answer to this question is c
6 0
3 years ago
Read 2 more answers
There are blue, red and white counters in a bag in the ratio 16 3 2 There are 112 more blue counters than white counters. How ma
olga nikolaevna [1]

We will have 16 white counters in the bag.

Given that there are  blue, red, and white counters in a bag in the ratio 16:3:2, the total number of balls will be:

  • Total = 16 + 3 + 2
  • Total  = 21

If there are <em>112 more blue counters than white counters</em>, then;

number of blues = number of white + 112

16x = 2x + 112

14x = 112

x = 8

Number of white counters = 2x = 2(8) = 16

Therefore we will have 16 white counters in the bag.

Learn more on ratios here: brainly.com/question/2914376

5 0
3 years ago
2 number cubes are rolled what is the probability that the sum if the numbers rolled is either a 4 or a 10
goldenfox [79]
With 2 cubes, there are 3 ways to roll a sum of 4... 1 and 3, 3 and 1, 2 and 2.
with 2 cubes, there are 3 ways to roll a sum of 10....6 and 4, 4 and 6, 5 and 5.

total possible outcomes = (6 * 6 ) = 36

probability of this happening is 6/36 reduces to 1/6
4 0
3 years ago
In a championship basketball game, Paula Zimmerman scored twice as many points as Maria Kaminsky. If the total number of points
Strike441 [17]

Answer:

x=34

y=17

Step-by-step explanation:

Let Paula's score be= x

Let Maria's score be=y

<u>Given</u><u>:</u>

x=2y

x+y=51

<u>Substitution</u><u>:</u>

2y+y=51

<u>Formula</u><u>:</u>

2y+y=51

3y=51

y=17

x=2y

x=2(17)

x=34

<u>Proof</u><u>:</u>

x+y=51

34+17=51

51=51

Hope this helps ;) ❤❤❤

5 0
3 years ago
25 Points ! Write a paragraph proof.<br> Given: ∠T and ∠V are right angles.<br> Prove: ∆TUW ∆VWU
vladimir2022 [97]

Answer:

Δ TUW ≅ ΔVWU ⇒ by AAS case

Step-by-step explanation:

* Lets revise the cases of congruent for triangles

- SSS  ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and  

 including angle in the 2nd Δ  

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ  

 ≅ 2 angles and the side whose joining them in the 2nd Δ  

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

 and one side in the 2ndΔ

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

 leg of the 2nd right angle Δ

* Lets solve the problem

- There are two triangles TUW and VWU

- ∠T and ∠V are right angles

- LINE TW is parallel to line VU

∵ TW // VU and UW is a transversal

∴ m∠VUW = m∠TWU ⇒ alternate angles (Z shape)

- Now we have in the two triangles two pairs of angle equal each

 other and one common side, so we can use the case AAS

- In Δ TUW and ΔVWU

∵ m∠T = m∠V ⇒ given (right angles)

∵ m∠TWU = m∠VUW ⇒ proved

∵ UW = WU ⇒ (common side in the 2 Δ)

∴ Δ TUW ≅ ΔVWU ⇒ by AAS case

7 0
3 years ago
Read 2 more answers
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