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3 years ago

Ms. Masse's biology class is conducting an experiment

1 answer:

6 0

2 + 2 + 2 + 2 + 2 = 10
Five days

2 + 2 + 2 + 2 + 2 + 2 + 2 = 14
Full week

10 x 2 = 20

14 x 2 = 28

The bacteria will double every day for a total of 20/28 bacteria on the last day.

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Someone please be awesome and help me please :(

solong [7]

Answer:

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared. Whatever you add in, you must take out.

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

Now we are read to write that one part (the first three terms together) as a square:

$(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

I don't see this but what happens if we find a common denominator for those 2 terms after the square. (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

$(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0$

They put it in ( )

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

I'm going to go ahead and combine those fractions now:

$(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0$

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

$(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0$

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

$x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}$

$x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}$

Now subtract b/(2a) on both sides:

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Combine the fractions (they have the same denominator):

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

6 0

3 years ago

T=m-n for n for the final answer

Snezhnost [94]

Answer:n=-t+m

Step-by-step explanation:

6 0

3 years ago

Multiplying and Dividing Rational Expressions<br> What is the product?

PolarNik [594]

rational numbers are always negative when u add irrational numbersStep-by-step explanation:

4 0

3 years ago

Solve the inequality n+3<-7

Aliun [14]

Answer:

Step-by-step explanation:

n<-7-3

n<-10

=> n= (-infinitive ; -10)

5 0

2 years ago

PLS HELP! GIVING BRAINLIST!

svlad2 [7]

Answer:

We conclude that (4, 2) is NOT a solution to the system of equations.

Step-by-step explanation:

Given the system of equations

$y = x - 2$

$y = 3x + 4$

Important Tip:

In order to determine whether (4, 2) is a solution to the system of equations or not, we need to solve the system of equations.

Let us solve the system of equations using the elimination method.

$\begin{bmatrix}y=x-2\\ y=3x+4\end{bmatrix}$

Arrange equation variables for elimination

$\begin{bmatrix}y-x=-2\\ y-3x=4\end{bmatrix}$

Subtract the equations

$y-3x=4$

$-$

$\underline{y-x=-2}$

$-2x=6$

Now, solve -2x = 6 for x

$-2x=6$

Divide both sides by -2

$\frac{-2x}{-2}=\frac{6}{-2}$

Simplify

$x=-3$

For y - x = -2 plug in x = -3

$y-\left(-3\right)=-2$

$y+3=-2$

Subtract 3 from both sides

$y+3-3=-2-3$

Simplify

$y=-5$

The solution to the system of equations is:

(x, y) = (-3, -5)

Checking the graph

From the graph, it is also clear that (4, 2) is NOT a solution to the system of equations because (-3, -5) is the only solution as we have found earlier.

Therefore, we conclude that (4, 2) is NOT a solution to the system of equations.

8 0

3 years ago