e follSOLUTION
Given the question in the image, the following are the solution steps to answer the question
STEP 1: Write the general equation of an ellipse

STEP 2: Identify the parameters
the length of the major axis is 2a
the length of the minor axis is 2b

STEP 3: Get the equation of the ellipse

STEP 4: Pick the nearest equation from the options,
Hence, the equation of the ellipse in the image is given as:

OPTION A
Hi there! The answer to this problem would be 36.64$.
Step By Step:
So there is three teachers and they all brought something.
_____________________________________
| Mrs.Maiers | 7.68$ |
| Mr.Lang | 11.52$ |
| Mrs.Connor | 17.64$ |
______________________________________
Total Cost: 36.64
Answer:
x = all real numbers because this equation is an identity
Step-by-step explanation:
9 (1/3) = 9*1/3 = 3
3 + 8x = 4(2x + 3/4)
3 + 8x = 8x + 3
x = all real numbers because this equation is an identity
200/160=1.25
200+160=360/1.25/160=200.8
so your answer is 0.8
Answer:
y = 2cos5x-9/5sin5x
Step-by-step explanation:
Given the solution to the differential equation y'' + 25y = 0 to be
y = c1 cos(5x) + c2 sin(5x). In order to find the solution to the differential equation given the boundary conditions y(0) = 1, y'(π) = 9, we need to first get the constant c1 and c2 and substitute the values back into the original solution.
According to the boundary condition y(0) = 2, it means when x = 0, y = 2
On substituting;
2 = c1cos(5(0)) + c2sin(5(0))
2 = c1cos0+c2sin0
2 = c1 + 0
c1 = 2
Substituting the other boundary condition y'(π) = 9, to do that we need to first get the first differential of y(x) i.e y'(x). Given
y(x) = c1cos5x + c2sin5x
y'(x) = -5c1sin5x + 5c2cos5x
If y'(π) = 9, this means when x = π, y'(x) = 9
On substituting;
9 = -5c1sin5π + 5c2cos5π
9 = -5c1(0) + 5c2(-1)
9 = 0-5c2
-5c2 = 9
c2 = -9/5
Substituting c1 = 2 and c2 = -9/5 into the solution to the general differential equation
y = c1 cos(5x) + c2 sin(5x) will give
y = 2cos5x-9/5sin5x
The final expression gives the required solution to the differential equation.